Answer: h(x) = 3*x^2 - 7*x + 8
Step-by-step explanation:
The rate of change of a function is equal to the derivate:
remember that a derivate of the form:
k(x) = a*x^n is k'(x) = n*a*x^(n-1)
Then we have:
f(x) = 2*x - 10
f'(x) = 1*2* = 2
g(x) = 16*x - 4
g'(x) = 1*16 = 16
h(x) = 3*x^2 - 7*x + 8
h'(x) = 2*3*x - 1*7 = 6*x - 7
So the only that increases as x increases is h(x), this means that the greates rate of change as x approaches inffinity is the rate of change of h(x)
We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
<span>90 + 35 = 125.
180 -125 = 55 degrees.
4.59^2 + 6.55^2 = 8^2
21.1 + 42.9= 64 inches</span>
Answer:
The slope intercept form is typically in the form of
y=mx+c
c=-2
m=4
The slope intercept form of the equation is
y=4x-2
X(2/3y)
factor out an x on both numerator and denominator
