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denis-greek [22]
3 years ago
10

Which is not a sign of a physical change? *

Chemistry
1 answer:
Ede4ka [16]3 years ago
5 0
Let's start off by having a look at the differences between chemical change and physical change.

The difference between a physical and chemical reaction is composition.
In a reaction, the composition of the  change, whereas in a  reaction, one may find change in the smell, appearance or type of matter without actual change in the composition. Despite the name, during a physical "reaction", no reaction is actually taking place. 

For something to be labelled a reaction, a change in the elemental composition of the substance has to experience a change.

ヽ Physical properties include many other aspects of a substance. Luster, malleability, ability to be drawn into a thin wire, density, viscosity, solubility, mass and volume are some physical properties. Any change in these physical properties is referred to as a physical change.

ヽ Physical changes are changes that result in a difference in display without changing the composition. Texture, color, temperature, shape or change of state (Boiling Point and Melting Point are significant factors in determining this change) are a few examples.

ヽ Chemical changes, on the other hand, are different. A chemical change occurs when the substance's composition is changed. When bonds are broken and new ones are formed, a chemical change occurs. Change in temperature, color, smell (after reaction has occurred) and the formation of a precipitate or bubbles are indicators of a chemical change.

Tracing back to your question;

~ Melting
Let's use the example of an ice cube melting.

When you melt an ice cube, you have a physical change because you're adding energy. Evidence of this is the phase change of solid to liquid; it signifies that you added enough energy for this phase change to occur.

~ Boiling
Let's use boiling water as an example.

When you boil water, it doesn't lose any of its properties. Rather, it simply undergoes a change in state during the process (the change of state being from liquid to gas). This tells us that boiling water is a physical change and not a chemical change.

~ Bubbles
When bubbles form, a change in temperature may also be taking place, as temperature change and the formation of bubbles often go hand-in-hand. An example of this may be the reaction below, in which the formation of gas bubbles (Carbon Dioxide) form.

<span>N<span>a2</span>C<span>O3 </span>+ 2HCl → 2NaCl + <span>H2</span>O + C<span>O2</span></span>

The formation of bubbles (gas being given off) is an indicator of a chemical reaction taking place.

~ Condensation
Condensation is the physical change of a substance in a gaseous state being changed into its liquid state as a result of energy being lost due to heat loss or applied pressure.

From the above explanations and examples, we can see that the formation of bubbles is the option which is  a sign of a physical change!

Your answer is the third option.

Hope this helps! <span>ッ</span>

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What is the predicted change in the boiling point of water when 1.50 g of
dezoksy [38]

Answer:

0.00735°C

Explanation:

By seeing the question, we can see the elevation in boiling point with addition of BaCl₂ in water

⠀

\textsf {While} \:  \sf  {\Delta T_b}  \: \textsf{expression is used} \\  \textsf {for elevation of boiling point}

⠀

⠀

<u>The</u><u> </u><u>elevation</u><u> </u><u>in</u><u> </u><u>boiling</u><u> </u><u>point</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>phenomenon</u><u> </u><u>in</u><u> </u><u>which</u><u> </u><u>there</u><u> </u><u>is</u><u> </u><u>increase</u><u> </u><u>in</u><u> </u><u>boiling</u><u> </u><u>point</u><u> </u><u>in</u><u> </u><u>solution</u><u>,</u><u> </u><u>when</u><u> </u><u>the</u><u> </u><u>particular</u><u> </u><u>type</u><u> </u><u>of</u><u> </u><u>solute</u><u> </u><u>is</u><u> </u><u>added</u><u> </u><u>to</u><u> </u><u>pure</u><u> </u><u>solvent</u><u>.</u>

⠀

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\sf  \large \underline{The \:  formula \: to \:  be  \: used \:  in \:  this \:  question \:  is}  \\   \boxed{T_b = i \times  K_b \times  m}

⠀

⠀

Where 'i' is van't hoff factor which represents the ratio of observed osmotic pressure and the value to be expected.

and 'i' is 3 (as given in the question)

⠀

'Kb' is molal boiling point constant. And it's value is 0.51°C/mol(given in question)

⠀

'm' represent the molality of solution. Molatity is no. of moles of solution present in 1kg of solution.

⠀

⠀

<u>To</u><u> </u><u>find</u><u> </u><u>molality</u><u>,</u><u> </u><u>we</u><u> </u><u>have</u><u> </u><u>to</u><u> </u><u>divide</u><u> </u><u>no</u><u>.</u><u> </u><u>of</u><u> </u><u>moles</u><u> </u><u>of</u><u> </u><u>solute</u><u> </u><u>by</u><u> </u><u>weight</u><u> </u><u>of</u><u> </u><u>solution</u>

⠀

While first we need to no. of moles

\sf \implies no. \: of \: moles =  \frac{weight \: of \: solute}{molar \: mass \: of \: solute}  \\  \\ \implies \sf no. \: of \: moles =  \frac{1.5}{208.23}  \\  \\  \sf \implies  no. \: of \: moles = 0.0072

⠀

⠀

<u>Now</u><u>,</u><u> </u><u>we</u><u> </u><u>will</u><u> </u><u>find</u><u> </u><u>molality</u>

⠀

\sf  \hookrightarrow molality =  \frac{no.\: of \: moles}{weight \: of \: solution}  \\  \\  \sf  \hookrightarrow molality =  \frac{0.072}{1.5}  \\  \\  \sf  \hookrightarrow molality = 0.048 \: mol {kg}^{ - 1}

⠀

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\textsf{ \large{ \underline{Now substituting the required values}}}

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\sf \longmapsto \Delta T_b = 3  \times 0.51  \times 0.0048 \\  \\ \\     \boxed{ \tt{ \longmapsto \Delta T_b =0.00735{ \degree}C}}

⠀

⠀

⠀

<u>Henceforth</u><u>,</u><u> </u><u>the</u><u> </u><u>change</u><u> </u><u>in</u><u> </u><u>boiling</u><u> </u><u>point</u><u> </u><u>is</u><u> </u><u>0</u><u>.</u><u>0</u><u>0</u><u>7</u><u>3</u><u>5</u><u>°</u><u>C</u><u>.</u>

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vlabodo [156]
When oxygen has an electronegativity of 3.5, and carbon has an electronegativity of 2.5, then the oxygen atom would have a slightly negative charge. The oxygen atom in  the carbon monoxide molecule would pull more electrons to its side since it has higher electronegativity making it slightly negative and the carbon would have a slightly positive charge as it would contain less electrons. This results to the formation of a polar molecule. A polar molecule is made when the molecule contains a slightly positive end and a slightly negative end. It would have a net dipole which is a result of the partial opposing charges in the molecule.
6 0
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in order to decrease the freezing point of 500. g of water to 1.00° c how many grams of ethylene glycol (C2H602)must be added (K
sesenic [268]

Answer:

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6 0
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Sonbull [250]
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7 0
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a sample of helium occupies a volume of 101.2 mL at a pressure of 790 mmHg. at what pressure would the volume be 120 mL?
AveGali [126]

Answer : The final pressure will be, 666.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 790 mmHg

P_2 = final pressure = ?

V_1 = initial volume = 101.2 mL

V_2 = final volume = 120 mL

Now put all the given values in the above equation, we get:

790mmHg\times 101.2mL=P_2\times 120mL

P_2=666.2mmHg

Therefore, the final pressure will be, 666.2 mmHg

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3 years ago
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