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Leno4ka [110]
3 years ago
12

TRUE OR FALSE? Alloys are used more than pure metals because they are generally softer and less likely to react with air or wate

r. WILL GIVE BRAINLIEST
Chemistry
2 answers:
d1i1m1o1n [39]3 years ago
8 0

Answer:

False

Explanation:

They’re used cause they’re generally harder than pure metals

Vitek1552 [10]3 years ago
5 0

Alloys are used much more than pure metals because they are generally <u>stronger</u> and less likely to react with air or water...

So I would say false

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Molarity formula what is the molarity of a solution in which 3 moles of nacl is dissolved in 1.5 kg of water
Igoryamba
Molarity is..
1.5 kg H₂O = 1.5L H₂O
So...
\frac{moles}{volume} = molarity
\frac{3.0 mol}{1.5L} = molarity
2M = molarity
7 0
3 years ago
Convert 99 moles of CO2 to atoms
lorasvet [3.4K]

Answer:

              1.78 × 10²⁶ Atoms

Explanation:

Relation between number of molecules and moles is,

No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol

No. of Molecules = 99 mol × 6.022 × 10²³ Molecules/mol

No. of Molecules = 5.96 × 10²⁵ Molecules

Also, In CO₂ Molecule there are 3 atoms.

So,

No. of atoms = 5.96 × 10²⁵ Molecules × 3

No. of atoms = 1.78 × 10²⁶ Atoms

3 0
2 years ago
How many carbon atoms are in the following molecule of isobutane? (ch3)3ch
STALIN [3.7K]
Number of Carbon atoms = 3*1 + 1 = 3 + 1 = 4

In short, Your Answer would be Option B

Hope this helps!
4 0
2 years ago
Read 2 more answers
1. Complete the following
Marat540 [252]

Answer:

\large \boxed{\text{0.603 mol}}

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of O₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:        180.16

           C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g:        18.1

(a) Moles of C₆H₁₂O₆

\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{18.1 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1005 mol C$_{6}$H$_{12}$O}_{6}

b) Moles of O₂

\text{Moles of O}_{2} =\text{0.1005 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol O}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.603 mol O}_{2}\\\\\text{The reaction requires $\large \boxed{\textbf{0.603 mol}}$ of oxygen}  

3 0
2 years ago
A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume
Kipish [7]

Answer:

Final pressure in (atm) (P1) = 6.642 atm

Explanation:

Given:

Initial volume of gas (V) = 12.5 L

Pressure (P) = 784 torr

Temperature (T) = 295 K

Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

\frac{PV}{T} =\frac{P1V1}{T1} \\\\\frac{(784)(12.5)}{295} =\frac{(P1)(2.04)}{310}\\\\33.22 = \frac{(P1)(2.04)}{310}\\\\P1=5,048.18877

⇒ Final pressure (P1) = 5,048.18877 torr

⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760

⇒ Final pressure in (atm) (P1) = 6.642 atm

3 0
3 years ago
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