Answer: 362,07 cm3
To answer this question you need to convert the lb into gram first. One lb equal to 453.592g, so: 3.6lb x 453.592gram/lb= 1632.9312gram.
Now we have mass(1632.9312g), density (4.51g/cm3). Volume is mass divided by density. The equation would be:
Volume= mass/density
Volume = 1632.9312gram / (4.51g/cm3)= 362,07 cm3
Answer:
Average rate of reaction is 0.000565 M/min
Explanation:
Applying law of mass action for the given reaction:
Average rate = ![-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO_{2}]}{\Delta t}=\frac{\Delta [O_{2}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5CDelta%20%5BNO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B%5CDelta%20%5BO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
Where, ![-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of disappearance of 
, ![\frac{1}{4}\frac{[NO_{2}]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5BNO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of appearance of 
and ![\frac{[O_{2}]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of appearance of 
Here,![-\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
= 
So average rate of reaction = ![[tex]-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=%5Btex%5D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
[/tex] = 
Li because its charge is +1.
Answer:
The initial temperature was 58.4°C
Explanation:
Given the following data:
initial volume = V₁ = 380 mL = 0.38 L
final volume = V₂ = 250 mL = 0.25 L
final temperature = T₂ = -55°C = 218 K
According to Charles's law, the volume of a gas is <em>directly proportional to the temperature</em> (in Kelvin). The mathematical expression is:
V₁/T₁= V₂/T₂
So, we calculate the initial temperature (V₁) as follows:
T₁ = T₂/V₂ x V₁ = 218 K/(0.25 L) x 0.38 L = 331.36 K ≅ 331.4 K
Finally, we convert the initial temperature from K to °C:
T₁= 331.4 K - 273 = 58.4°C
Answer:
The change in entropy of gas is 
Explanation:
n= Number of moles of gas
Change in entropy of gas = 
From the given,
Let "T" be the initial temperature.
Therefore, The change in entropy of gas is
