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2 years ago

Solve for X using either sine, cosine, or tangent

Mathematics

1 answer:

vovikov84 [41]2 years ago

7 0

Answer:

•12.12

•56.92

Step-by-step explanation:

•Sin 30° = x ÷ 14√3

x=14√3 *Sin30

x=7√3

x=12.12

•Tan30°=6√3÷x

x=6√30 ÷Tan 30

x=18√10

x=56.92

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How much Zn and how much HCl should be used to produce 1.5 g ZnCl2

tatuchka [14]

Answer:

0.71963 g of Zn
0.80256 g of HCl

Step-by-step explanation:

The required mass of reactants can be computed from the number of moles of product.

moles of ZnCl₂ = (1.5 g)/(136.282 g) ≈ 0.0110066 moles

Then the mass of Zn required is ...

mass of Zn = (0.0110066 mol)(65.382 g/mol) = 0.71963 g

Two moles of HCl are used in the reaction with each mole of Zn, so the mass of HCl required is ...

mass of HCl = 2(0.0110066 mol)(36.458 g/mol) = 0.80256 g

_____

<em>Comment</em>

The discrepancy in the last two decimal places of the weights above versus the calculator output below comes from rounding of moles of Zn to 4 significant digits, instead of 5 or more. The number of moles of ZnCl₂ is closer to 0.0110066.

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2 years ago

PLZ HELP!!! Write a scenario from the equation y=12x+5

Ad libitum [116K]

Answer:

Mary has 12 times the apples plus 5

Step-by-step explanation:

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#CarryOnLearning

#BrainlyMathKnower

#5-MinutesAnswer

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2 years ago

Two mathematical questions attached below.

BartSMP [9]

Answer:

See below

Step-by-step explanation:

$9.( {m}^{3} {n}^{5} )^{ \frac{1}{4} } \\ = m^{\frac{3}{4}}n^{\frac{5}{4}}\\ \\ 10. \sqrt[5]{ \sqrt[4]{x} } \\ = \sqrt[5]{ {x}^{ \frac{1}{4} } } \\ = {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} } \\ = {x}^{ \frac{1}{4} \times \frac{1}{5} } \\ = {x}^{ \frac{1}{20} } \\ \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } } \\ = \sqrt[5]{ {a}^{ \frac{2}{3} } } \\ = {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} } \\ = {a}^{ \frac{2}{3} \times \frac{1}{5} } \\ = {a}^{ \frac{2}{15} }$

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