All categories

2 years ago

Find the slope of the line that passes through (9,6) and (5,15)

Mathematics

1 answer:

Mars2501 [29]2 years ago

7 0

Step-by-step explanation:

let x1=9 y1=6

x2=5 y2=15

now we khow that

slope (m) =y2-y1/x2-x1

= 15-6/5-9

=9/-4 ans

You might be interested in

What is the solution to the following system of equations?

adelina 88 [10]

-x^2 - 5x - 4 = -x^2 + 9x - 18
-5x - 9x = -18 + 4
-14x = -14
x = -14/-14
x = 1 <====

y = -x^2 - 5x - 4
y = (-1^2) - 5(1) - 4
y = 1 - 5 - 4
y = 1 - 9
y = -8 <====

8 0

3 years ago

Simplify <br> 6 minus the square root of 25 over 4<br> I would appreciate some help :)

marshall27 [118]

6-5 (the square root of 25) is 1, so the answer is 1/4 or 0.25

8 0

3 years ago

What is the value of the underline digit?<br><br> 119.65

kipiarov [429]

1 1 9 . 6 5
1 is the the hundreds place
1 is the tens place
9 is the ones place
6 is the tenths place
5 is the hundredths place

4 0

2 years ago

Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers

Ilia_Sergeevich [38]

Given:

The line passes through (-3,-6) and (2,-2).

To find:

The equation of line.

Solution:

If a line passes through two points $(x_1,y_1)\text{ and }(x_2,y_2)$ , then the equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through (-3,-6) and (2,-2). So, the equation of line is

$y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))$

$y+6=\dfrac{-2+6}{2+3}(x+3)$

$y+6=\dfrac{4}{5}(x+3)$

$y+6=\dfrac{4}{5}(x)+\dfrac{4}{5}(3)$

Subtract 6 from both sides.

$y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6$

$y=\dfrac{4}{5}(x)+\dfrac{12-30}{5}$

$y=\dfrac{4}{5}(x)+\dfrac{-18}{5}$

$y=\dfrac{4}{5}(x)-\dfrac{18}{5}$

Therefore, the equation of line is $y=\dfrac{4}{5}(x)-\dfrac{18}{5}$ .

3 0

3 years ago

240,000 written as 10th power

kirill115 [55]

The answer is 24 to the 4th power

3 0

3 years ago