All categories

3 years ago

I need help now it’s an iready

Mathematics

1 answer:

schepotkina [342]3 years ago

3 0

answer:

21 + 3x (you would not put the x again since it is already given)

step-by-step explanation:

we have to distribute 3 to the expression in the parenthesis

3 (7 + x)

= 21 + 3x

this will be the expression once we distribute

You might be interested in

What is the greatest common factor (GCF) of 72 and 44? A. 4 B. 3 C. 2 D. 1

SCORPION-xisa [38]

Answer:

A. 4

Step-by-step explanation:

72 = 2 * 2 * 2 * 3 * 3

44 = 2 * 2 * 11

GCF = 2 * 2

GCF = 4

3 0

3 years ago

Ill mark brainliest<br><br> what is the benefit of using an augmented matrix in a linear equation

nadezda [96]

They simplify operations when the systems are not encumbered by the variables.

4 0

3 years ago

Read 2 more answers

What is the area of the fire pit? (Use 3.14 for pi.)

laila [671]

Answer:

$Area = 65.94$

Step-by-step explanation:

I will assume that the shaded region is the fire pit

Given

$R = 5$

$r = 2$

Required

Determine the area of the fire pit

First, calculate the area of the big circle.

$A_2 = \pi R^2$

Area of the small is:

$A_1 = \pi r^2$

The area of the pit is:

$Area = A_2 - A_1$

$Area = \pi R^2 - \pi r^2$

$Area = \pi (R^2 - r^2)$

$Area = 3.14 (5^2 - 2^2)$

$Area = 3.14 (25 - 4)$

$Area = 3.14 * 21$

$Area = 65.94$

5 0

3 years ago

Log(5x-4)-log(×+1)=log4

Anna007 [38]

Answer:

x = 8

Step-by-step explanation:

log(5x-4)-log(x+1)=log 4

log [ (5x - 4) / (x+ 1) ] = log 4

[ log (a/b) = loga - logb]

(5x - 4 ) / ( x + 1) = 4

(5x - 4) = 4x + 4

5x - 4x = 4 + 4

x = 8

Hope it will help :)❤

4 0

3 years ago

Of 375 randomly selected students, 30 said that they planned to work in a rural community. Find 95% confidence interval for the

Artemon [7]

Answer:

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 375, \pi = \frac{30}{375} = 0.08$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 - 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.0525$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 + 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.1075$

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

4 0

3 years ago