Answer:
There were 63.67 kJ liberated
If 1 mol of toluene was burned, there would be liberated 3906 kJ / mole
Explanation:
Step 1: Data given
Mass of the toluene sample = 1.500 grams
The temperature of the calorimeter rose from 25.000 °C to 26.413 °C
<em>Write the balanced chemical equation for the reaction in the calorimeter.</em>
C7H8(l) + 9O2(g) ⇒ 7CO2(g) + 4H2O(l)
<u>Step 2:</u> Calculate Q of the calorimeter
Q = C * Δt
Q = 45.06 kJ/ °C * ( 26.413 - 25)
Q =<u> 63.67 kJ
</u>
<u>Step 3:</u> Calculate moles of toluene
Moles toluene = mass toluene / molar mass toluene
Moles toluene = 1.500 grams /92.14 g/mol
Moles toluene = 0.0163 moles
<u>Step 4:</u> Calculate energy per mole
energy per mole = 63.67 kJ / 0.0163 moles = 3906 kJ / mole
