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garik1379 [7]
3 years ago
15

PLEASE HELP!!!!!!!!!! How does the words used in a text help the theme, setting, and plot?

Chemistry
2 answers:
Julli [10]3 years ago
4 0
The one above me is the answe
yKpoI14uk [10]3 years ago
3 0
It emphasizes the word and shows that it has meaning. emphasizing it makes you drawn to it more.
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What is national flower of nepal?
Vanyuwa [196]

Answer:

national flower : Rhododendron

national animal : cow

national bird : Himalayan Monal

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2 years ago
Which sample of matter is classified as a substance?<br> (1) air (3) milk(2) ammonia (4) seawater
jeyben [28]
A chemical substance has the characteristics that it cannot be separated by physical  methods. Seawater and milk can be separated by sedimentation, and air has different components depending on other aspects (such as elevation). Only ammonia is a substance. (thus it can have a formula: NH<span>3)</span>
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2 years ago
Which of the following will form a cation
sdas [7]

D) Calcium

hope this helps :)

3 0
3 years ago
What is the conclusive evidence that mixing sugar in the water is a physical change
djyliett [7]
THE DEFINITION OF PHYSICAL CHANGE: Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds. so the answer is that the form of the sugar is changing in water but if you boiled the water till its all evaporated all that will be left is the sugar
8 0
3 years ago
If a 45 mM phosphate solution(solution A) had an absorbance of 1.012. What would be the absorbance if 11 mL of solution A was us
timofeeve [1]

Answer:

0.550

Explanation:

The absorbance (A) of a substance depends on its concentration (c) according to Beer-Lambert law.

A = ε . <em>l</em> . c

where,

ε: absorptivity of the species

<em>l</em>: optical path length

A 45 mM phosphate solution (solution A) had an absorbance of 1.012.

A = ε . <em>l</em> . c

1.012 = ε . <em>l</em> . 45 mM

ε . <em>l</em>  = 0.022 mM⁻¹

We can find the concentration of the second solution using the dilution rule.

C₁ . V₁ = C₂ . V₂

45mM . 11mL = C₂ . 20.0 mL

C₂ = 25 mM

The absorbance of the second solution is:

A = (ε . <em>l</em> ). c

A = (0.022 mM⁻¹) . 25 mM = 0.55 (rounding off to 3 significant figures = 0.550)

8 0
3 years ago
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