How much money did juan open her account with, and how much money did she deposit each week?

I attended a funeral once in Pickens county in my State.... They buried him in the midst of a marble quarry: they cut through so

UNO [17]

Answer:

C

Step-by-step explanation:

Now we have improved on that. We have got the biggest marble-cutting establishment on earth within a hundred yards of that grave. We have got a half-dozen woolen mills right around it, and iron mines, and iron furnaces, and iron factories. We are coming to meet you. We are going to take a noble revenge, as my friend, Mr. Carnegie, said last night, by invading every inch of your territory with iron, as you invaded ours twenty-nine years ago.

7 0

2 years ago

Read 2 more answers

Solve –2 + x > 10 using the properties of inequalities.

lys-0071 [83]

Using the properties of inequalities:
Subtract -2 from each side of the inequality -2 + x > 10
Remember -2 - -2 becomes -2 + 2 = 0 - -2 + x > --2
10 - -2 becomes 10 + 2 =12 0 + x > 12
So the final solution would be x > 12.
Therefore x would have to be all numbers greater than 12.

4 0

2 years ago

Math help me please you will be mark as the brainiest I do not have much time left

Black_prince [1.1K]

A little tip: you should put the question in next time :)!

7 0

2 years ago

The chances of a tax return being audited are about 21 in 1 comma 000 if an income is less than $100,000 and 29 in 1 comma 000

vladimir2022 [97]

Answer:

a) p=0.021

b) p=0.029

c) Exactly one audit: P=0.0965

More than one audit: P=0.0042

Step-by-step explanation:

a) If the income is less than $100,000, there is a probability of 21 in 1,000 of being audited. This is:

$p_1=\dfrac{21}{1,000}=0.021$

If the income is equal or more than $100,000, there is a probability of 29 in 1,000 of being audited. This is:

$p_2=\dfrac{29}{1,000}=0.029$

b) If we have 5 taxpayers with incomes under $100,000, and we want to know the probability that exactly one will be audited, we can model this a binomial randome variable, with p=0.021 and n=5:

$P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\$

There is a probability of 0.0965 that exactly one out of a sample of five taxpayers with incomes under $100,000 will be audited.

To calculate the probability that more than one will be audited, we use the same distribution:

$P(x>1)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0) = \dbinom{5}{0} p^{0}q^{5}=1*1*0.8993=0.8993\\\\\\P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\\\P(x>1)=1-[P(x=0)+P(x=1)]\\\\P(x>1)=1-(0.8993+0.0965)\\\\P(x>1)=1-0.9958\\\\P(x>1)=0.0042$

There is a probability of 0.0042 that more than one out of a sample of five taxpayers with incomes under $100,000 will be audited.

8 0

2 years ago

Divide 7/15 by 3/5 = A. 7/9 B. 21/75 C. 75/21 D. 7/25

luda_lava [24]

Answer:

a

Step-by-step explanation:

7/15. /3/5=7/15*5/3 =7/9

5 0

2 years ago