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dybincka [34]
3 years ago
10

What is an equation of the line that passes through the point (-5,-3)(−5,−3) and is parallel to the line 3x+5y=15

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

  • y = -3/5x - 6 or 3x + 5y = -30

Step-by-step explanation:

<u>Given line:</u>

  • 3x + 5y = 15

<u>Converting into slope-intercept form:</u>

  • 3x + 5y = 15
  • 5y = - 3x + 15
  • y = -3/5x + 3

<u>Parallel lines have the same slope, so the parallel line will be:</u>

  • y = -3/5x + b

<u>Using given point (-5, -3) finding the y-intercept:</u>

  • -3 = -3/5(-5) + b
  • -3 = 3 + b
  • b = -3 - 3
  • b = -6

<u>So the line is:</u>

  • y = -3/5x - 6

<u>Or converted into standard form:</u>

  • y = - 3/5x - 6
  • 3/5x + y = -6
  • 3x + 5y = -30
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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

y = -4x + 3;

the slope of this equation is -4

we want the slope perpendicular to this

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