A, energy stored in chemical bonds of molecules, is correct because chemical energy is the potential energy in the molecule, for example the chemical energy in coal is converted to electrical energy through power plants. The energy was already stored in the coal, just in a different form.
Answer:
Anhydride, any chemical compound obtained, either in practice or in principle, by the elimination of water from another compound. Examples of inorganic anhydrides are sulfur trioxide, SO3, which is derived from sulfuric acid, and calcium oxide, CaO, derived from calcium hydroxide
Explanation:
<h3>
<em><u>examples</u></em><em><u>.</u></em></h3>
1)acid anhydride.
2)basic anhydrides.
<h3>
<em><u>reactions</u></em><em><u>. </u></em></h3>
1)reaction with water
(CH3CO)2O + H2O → 2 CH3CO2H.
Answer:
Final temperature = T₂ = 328.815 K
Explanation:
Given data:
Given energy = 980 KJ = 980×1000= 980000 J
Volume = 6.2 L
Initial temperature =T₁= 291 K
Specific heat of water = 4.18 j /g .K
Final temperature = T₂ = ?
Formula:
Q = m. c . ΔT
ΔT = T₂ - T₁
we will first convert the litter into milliliter
6.2 × 1000 = 6200 mL
It is given in question that
1 mL = 1 g
6200 mL = 6200 g
Now we will put the values in formula,
Q = m. c . (T₂ - T₁)
980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)
980000 j = 25916 j/ k . (T₂ - 291 K)
980000 j / 25916 j/ k = T₂ - 291 K
37.8145 K + 291 K =T₂
T₂ = 328.815 K
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Answer:
Your answer would be a). 2.0 × 10-9
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Work:
In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.
You would use the ph (4.48) to find the ka for "hbro"
[H+]
=
10^-4.48
=
3.31 x 10^-5 M
=
[BrO-]
or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]
Then you would find ka:
(3.31 x 10^-5)^2/0.55 =2 x 10^-9
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<em>-Julie</em>
The required mole ratio of NH₃ to N₂ in the given chemical reaction is 2:4.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the number of entities present on the reaction before and after the reaction.
Given chemical reaction is:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
From the stoichiometry of the reaction it is clear that:
4 moles of NH₃ = produces 2 moles of N₂
Mole ratio NH₃ to N₂ is 2:4.
Hence required mole ratio is 2:4.
To know more about mole ratio, visit the below link:
brainly.com/question/504601
