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3 years ago

Which of the following orbitals is possible in an electron configuration? 4p 1p 3f O 2d

Chemistry

1 answer:

Korolek [52]3 years ago

6 0

Answer:

Explanation:

The possible orbitals in an electronic configuration must include:

A principle quantum number (n) , azimuthal quantum number (l) which is (0-n-1) , magnetic quantum number (m) which is (-l to +l) and spin quantum number.

Taking about 1p

n = 1

Possible value of l = 0 which is s orbital. Hence, it is not possible.

Taking about 3f

n = 3

Possible value of l = 0 , 1 and 2 which is s , p and d orbitals. Hence, it is not possible.

Taking about 2d

n = 2

Possible value of l = 0 and 1 which is s and p orbitals. Hence, it is not possible.

The only possible is 4 p in which all quantum numbers are justified.

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MaRussiya [10]

Answer:

Number of contraction cycles that could theoretically be fueled by the complete combustion of one mole of glucose is around 17

Explanation:

Energy released during the complete combustion of 1 mole glucose = 2870 kJ

Energy required/muscle contraction cycle = 67 kJ/contraction

Energy conversion efficiency = 39%

Actual amount of energy converted to contraction per mole of glucose is:

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Total contraction cycles fueled by the above energy is:

$=\frac{1119.3\ kJ}{67\ kJ/contraction} =16.7\ i.e.\ around\ 17\ contractions$

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3 years ago

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Phoenix [80]

Answer:

after 4 half-lives, 125g is left

Explanation:

The half-life of a radioactive substance is the time it takes for the substance to decay by half its original mass.

In this example, we are asked to find the remaining mass after four half-lives.

What we will simply do is to reduce the starting mass by half, after each half-life decay. this is done as follows:

1st half-life decay: starting mass 2000g

final mass = 2000g ÷ 2 = 1000g

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3rd half-life decay: starting mass = 500

final mass = 500 ÷ 2 = 250g

4th half-life decay: starting mass = 250g

final mass = 250 ÷ 2 = 125g

∴ after 4 half lives, 125g is left

3 0

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<span>The esters need to evaporate to be smelled.</span>

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Answer:

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