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mixer [17]
3 years ago
5

A sample of argon, Ar, has a volume of 5.40 L with an unknown pressure. The gas has a volume of 9.73 L when the pressure is 3.62

atm,
with no change in temperature and amount of gas. What was the initial pressue in atm of the gas?
O a. 6.523 atm
O b. 6.52 atm
Oc 2.009 atm
Od. 2,01 atm
Chemistry
1 answer:
ella [17]3 years ago
7 0

Answer:

<h2>6.52 atm</h2>

Explanation:

The initial pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the initial pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

From the question we have

P_1 =  \frac{9.73 \times 3.62}{5.40}  =  \frac{35.2226}{5.40}  \\  =6.522703...

We have the final answer as

<h3>6.52 atm</h3>

Hope this helps you

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