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Ivahew [28]
3 years ago
12

Find the area of the semicircle need help asapp

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

2 pi

Step-by-step explanation:

The radius is 2

The area of a circle is

A = pi r^2

We have 1/2 of a circle so

1/2 A = 1/2 pi r^2

         =1/2 pi ( 2)^2

         =1/2 pi *4

      = 2 pi

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Simplify<br> x + x + y y
kolezko [41]

Answer:

2x+2y

Step-by-step explanation:

x+x = 2x

y+y = 2y

2x+2y

4 0
3 years ago
What is the answer to number 2
MAXImum [283]
The answer would be B
4 0
3 years ago
Read 2 more answers
How do you determine whether a sum will be positive, negative, or 0 when adding a positive and a negative integer?
professor190 [17]
If the integers have the same absolute value ... they're the same number
but with different signs ... then their sum is zero.

Example:    (plus) 927 added to (negative) 927  =  zero


If the integers have different absolute values ... they're different numbers with different
signs ... then their sum has the same sign as the one with the bigger absolute value.

Examples:

==>   (plus) 92 added to (negative) 91
         92 and 91 are 1 number apart on the number line.
         The positive number is bigger than the negative number.
         So the sum is  +1 . 

==>    (plus) 35 added to (negative) 37
          35 and 37 are 2 numbers apart on the number line.
          The negative number is bigger than the positive one.
          So the sum is  -2 .
3 0
3 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
Help me with this please!
DedPeter [7]

Answer:

Area of triangle = 20√2

Step-by-step explanation:

Formula:

Area of triangle = bh/2

b - base  of triangle

h - height of triangle

<u>Distance formula</u>

d = √(x₂ - x₁)² +(y₂ - y₁)²

From the figure we can see that, the given triangle is right angled triangle.

Base = AC and Height = AB

<u>To find AB and AC</u>

A(1,3), B(4,7) and C(9, -5)

AB =  √(4 - 1)² +(7 - 3)² =  √(3² + 4²) = 5

AC = √(9 - 1)² +(-5 - 3)² =  √(8² + -8²) = 8√2

<u>To find the are of triangle</u>

Area = bh/2 = (5* 8√2)/2 = 20√2

Therefore the area of triangle = 20√2 square units

8 0
3 years ago
Read 2 more answers
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