Let the first brother = x
second brother = x + 2
third brother = x + 4
<span>The product of the first and third boys' ages is 20 more than twice the second boy's age:
x(x+4) = 2(x+2) + 20
x</span>² + 4x = 2x + 4 + 20
x² + 4x - 2x - 24 = 0
x² + 2x - 24 = 0
(x - 4)(x + 6) = 0
x = 4 or -6 (rejected, age cannot be negative)
First brother = 4
Second brother = 4 + 2 = 6
Third brother = 4 + 4 = 8
The three boys are 4, 6, and 8 years old.
It would be B.
The 6 and 9 look the same up side down and so do the HOH
<h2><u>The solution set to inequality is:</u></h2>
<em><u>Solution:</u></em>
<em><u>Given inequality is:</u></em>
We have to find the solution set to inequality
From given,
Expand
<em><u>Thus the solution set is:</u></em>
Answer:
1.2
Step-by-step explanation:
1.2 is answer but you can simplify to 1 1/5
Answer:
2
Step-by-step explanation:
-6 divided by a positive number would make it a positive number welcome
