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N76 [4]
3 years ago
12

Help please ⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️​

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0

one hour 55 min

you just need to subtract bout to get the answer

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How to solve for x and y
Nutka1998 [239]

Answer:

x = 26.4      y= 17

Step-by-step explanation:

Set up proportions.


To find x:

Set 12 over x is equal to 10 over 22.


12 times 22 = 264

264 / 10  =x


x =  26.4


To find y:

Set y over 37.4 is equal to 10 over 22.


37.4 times 10 =  374


374 / 22


y = 17

6 0
3 years ago
Y = -5x<br> y = x-6<br> What is the answer
deff fn [24]

Answer:

(1,-5)

Step-by-step explanation:

8 0
3 years ago
Find the value of y if the measure of the vertex angle is 64 degrees and base angle is (2y -11)
Dafna1 [17]

Answer: 35


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105 = 3y

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5 0
3 years ago
A random sample of 121 students from the University of Oklahoma had a sample mean ACT score of 23.4 with a sample standard devia
Grace [21]

Answer:

(22.74,24.06) is the required 95% confidence interval for the population mean ACT score of University of Oklahoma students.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 121

Sample mean = 23.4

Sample standard deviation = 3.65

Level of significance = 0.05

Degree of freedom

= n - 1 = 120

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Calculation of critical value:

t_{critical}\text{ at degree of freedom 120 and}~\alpha_{0.05} = \pm 1.9799  

Putting the values, we get,  

23.4\pm 1.9799(\dfrac{3.65}{\sqrt{121}} )\\\\ = 23.4 \pm 0.6569\\\\ = (22.7431 ,24.0569)\approx (22.74,24.06)  

(22.74,24.06) is the required 95% confidence interval for the population mean ACT score of University of Oklahoma students.

5 0
3 years ago
HEEEEELP PLEASEEEE THAAAAAAANK YOUUUUU
Nuetrik [128]

Answer:

250/30= 25/3

inverse of 25/3= 3/25

Step-by-step explanation:

3 0
3 years ago
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