Answer:
E=7453.99 V/m
Explanation:
The electric field on the charged is given by
E= Kqx/(r^2 +x^2)^3/2
Where;
K= constant of Coulomb's law
q= magnitude of charge= 30.0×10^-9 C
r= radius of the rings= 5 cm or 0.05m
x= distance between the rings = 18cm = 0.18 m
Substituting values;
E= 9.0×10^9 × 30.0×10^-9 × 0.18 / [(0.05^2 + (0.18)^2]^3/2
E= 48.6/(2.5×10^-3 + 0.0324)^3/2
E= 48.6/(0.0025 + 0.0324)^3/2
E= 48.6/6.52×10^-3
E=7453.99 V/m
D) sepals
other options are ridiculous
Answer:
B) an explanation for observable phenomena.
Explanation:
All theories have been stated by experiments and natural phenomenas.
Answer:
65 m/s
Explanation:
The motion of the supply along the horizontal direction is a uniform motion with constant speed. Therefore, its horizontal velocity is given by
where
d is the distance travelled horizontally
t is the time taken
In this problem, d = 650 m and t = 10 s, so if we apply the formula we get
The answer is -0.13
Hope this helps