HELP ASAP! BRINALIST!

Tectonic plates move due to _____ forces. A. internal B. external C. destructive D. constructive

Oliga [24]

Internal forcessssssssssss

6 0

4 years ago

78. A film of oil on water will appear dark when it is very thin, because the path length difference becomes small compared with

Hoochie [10]

To solve this problem it is necessary to apply the concepts related to the condition of path difference for destructive interference between the two reflected waves from the top and bottom of a surface.

Mathematically this expression can be described under the equation

$\delta = 2nt$

Where

n = Refractive index

t = Thickness

In terms of the wavelength the path difference of the reflected waves can be described as

$\delta = \frac{\lambda}{4}$

Where

\lambda = Wavelenght

Equation the two equations we have that

$2nt = \frac{\lambda}{4}$

$t = \frac{\lambda}{8n}$

Our values are given as

$\lambda = 380nm \rightarrow$ Wavelength of light

$n = 1.4$

$t = \frac{380nm}{8*1.4}$

$t = 33.93nm$

Therefore the minimum thickness of the oil for destructive interference to occur is approximately 34.0 nm

4 0

3 years ago

This mathematical model describes the changes that occur in a sample of

Veseljchak [2.6K]

Answer:

the correct answer is B

Explanation:

The kinetic model of the movement describes that the movement of the molecules increases with the increase of their internal energy, which in a macroscopic sample is reflected in an increase in the temperature of the sample.

The sample graph shows the function of temperature over time, which is why our kinetic model establishes that there is an increase in the movement of water molecules.

Consequently the correct answer is B

8 0

3 years ago

True or False: An example of an Isometric movement is a plank. please help 2 mins left!<br> PE

Anon25 [30]

Answer:

Yes

Explanation:

The plank (also called a front hold, hover, or abdominal bridge) is an isometric core strength exercise that involves maintaining a position similar to a push-up for the maximum possible time

5 0

3 years ago

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Suppose you now take the ball and using a bat, pop it straight up into the air with a hang-time of 5.00 s (the hang time is how

dolphi86 [110]

Answer:

Explanation:

Using the equation of motion formula $S = ut + \frac{1}{2}gt^2$ where;

S is the height to which the ball rises

u is the initial velocity of the ball = 0m/s

a is the acceleration due to gravity = 9.81m/s²

t is the time taken by the ball in air = 5.0s

Note that the time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s

Substituting the given parameters into the formula above to get S:

$S = ut + \frac{1}{2}gt^2\\\\S = 0(2.5)+ \frac{1}{2}(9.81)(2.5)^2\\\\S = 0+\frac{1}{2}(9.81)\times 6.25 \\\\S = \frac{61.3125}{2}\\ \\S = 30.65625m\\\\S \approx 30.66m$

This means that the ball rises 30.66m before it reaches its peak.

8 0

3 years ago