Answer:
4km
Explanation:
15 minutes is 1/4 of an hour.
1/4 of 16 is 4.
as it is given that


now we will have

now the magnitude of this vector is given as


now to find the direction we can use




The amount of extra electrons present on the negative surface is
57.2 x
.
Distance =1.6 cm
Side = 24 cm
Electric field = 18000 N/C
Calculating the capacitance in the metal plates is necessary.
Using the capacitance formula

Putting the value
C = 8.85 x
x (24 x 
/1.6 x 
C = 0.318 x
F
<h3>Calculation of potential</h3>
V = Ed
V = 18000 x 1.6 x
V
V = 288 V
<h3>Calculation of charge</h3>
Q = CV
Q = 0.318 x
x 288
Q = 91.54 x
C
Charge on the both the plates
Q = +91.54 x 
Q = - 91.54 x 
Calculation of excess electrons on the negative surface:
n = q/e
n = 91.54 x
/ 1.6 x 
n = 57.2 x
electrons
Hence, the number of excess electrons on the negative surface is
57.2 x
.
Learn more about capacitance here:
brainly.com/question/14746225
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Answer:
The formula of nitrogen trifluoride is NF 3
The formula of ammonia is NH3
The formula of magnesium hydroxide is Mg(OH)2
Explanation:
The formula of a compound refers to the correct representation of the compound using appropriate chemical symbols.
The formula of a compound is derived from the symbols of its constituent elements. The formula of the compound must correctly show the number of atoms of each element in one formula unit of the compound.
In the answer section, the correct names or formulas of some compounds have been shown
Answer:
The cart moved away from the starting point between 8 s and 10 s.
Explanation:
Given that :
Which of these does NOT describe the cart’s motion on this graph?
The cart was at rest between 5 s and 7 s : From the distance of golf cart Vs time graph ; the car was at rest between 5s and 7s as the graph was flat with that time interval, meaning there was no change in distance.
The cart moved toward the starting point between 7 s and 12 s. : The graph depicts a negative slope at this time interval as the distance from starting point fell from about 26 m to 10 m
The cart moved away from the starting point between 8 s and 10 s. : At this time interval, the cart moved towards the starting not and not away. This could be seen in the decrease in Distance from starting point between the tune interval.
The cart moved away from the starting point between 2 s and 5 s. - - > The cart moved away from the starting point, with the positive slope signifying an increase in distance.
Therefore, The cart moved away from the starting point between 8 s and 10 s does not describe the motion of the cart on the graph.