something through 1-10. i think its 7 but i rlly dont know. Sry.
9514 1404 393
Answer:
30 small chairs and 24 large chairs
Step-by-step explanation:
Let x and y represent the numbers of small chairs and large chairs built in a day. Then the relations for using available time are ...
20x +50y = 30×60
60x +90y = 66×60
Removing common factors, these can be written in standard form as ...
2x +5y = 180
2x +3y = 132
Subtracting the second equation from the first gives ...
2y = 48
y = 24 . . . . . divide by 2
Using the first equation to find x, we have ...
2x +5(24) = 180
2x = 60 . . . . . . . . . . subtract 120
x = 30 . . . . . . . . divide by 2
The company can build 30 small chairs and 24 large chairs in a day.
Answer:
2.73
Step-by-step explanation:
2.72(6)03
use 6= 2.73
First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2