The answer is 5/3 can I have the some points
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
Answer:
5.48
Step-by-step explanation:
add 2.98 1.75 and 0m75
Answer: 4y2z2 • (2x + y) • (4x2 - 2xy + y2) i think.hope it was helpful.
Step-by-step explanation:
Answer:
$8.53
Step-by-step explanation:
The first thing you do is convert the oz into pounds. There is 16 oz in a pound so our fraction is 9/16 which is 0.5625 . Then adding to the pounds it becomes 6.5625 pounds. Then multiply by 1.3.
