Can anybody solve this with explanation<br> 12600 × 11/10 × 11/10

A plant costs p dollars and a bush costs b dollars. Ana buys 2 plants and 4 bushes for $42. Paola buys 7 plants and 9 bushes for

gregori [183]

Answer:

p = 5 and b = 8

Step-by-step explanation:

First, create a system of equations:

2p + 4b = 42

7p + 9b = 107

Solve by elimination by multiplying the top equation by -7 and the bottom equation by 2:

-14p - 28b = -294

14p + 18b = 214

Add these together, and solve for b:

-10b = -80

b = 8

Plug in 8 as b into one of the equations, and solve for p:

2p + 4b = 42

2p + 4(8) = 42

2p + 32 = 42

2p = 10

p = 5

So, p = 5 and b = 8

4 0

2 years ago

Read 2 more answers

The function f(x) is graphed on the coordinate plane.

soldier1979 [14.2K]

Answer:

f(-4) = 4

Step-by-step explanation:

Fro the graph attached,

We have to calculate the value of the function at x = -4.

As we can find from the graph at the input value x = -4, output value of the function is f(-4) = 4

Therefore, f(-4) = 4 will be the answer.

5 0

2 years ago

Please I need help on this

Sonja [21]

The first one is 9k cause you’re multiplying it and the second one is -18 because you’re multiplying -2 and 9

3 0

2 years ago

Read 2 more answers

There are 12 ballons in a bag: 3 each of blue,green,red, and yellow.Three ballons are chosen at random. Find the probability tha

marin [14]

The answer would be 3/12

8 0

3 years ago

A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the Un

WINSTONCH [101]

Answer:

Part 1: The statistic

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=35+35-2=68$

Replacing we got

$t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31$

Part 2: P value

Since is a right tailed test the p value would be:

$p_v =P(t_{68}>4.31)=0.000022 \approx 0.00002$

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

Step-by-step explanation:

Data given

$\bar X_{1}=5135$ represent the mean for four year college

$\bar X_{2}=4436$ represent the mean for two year college

$s_{1}=783$ represent the sample standard deviation for four year college

$s_{2}=553$ represent the sample standard deviation two year college

$n_{1}=35$ sample size for the group four year college

$n_{2}=35$ sample size for the group two year college

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the mean enrollment at four-year colleges is higher than at two-year colleges in the United States , the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We can assume that the normal distribution is assumed since we have a large sample size for each case n>30. So then the sample mean can be assumed as normally distributed.

Part 1: The statistic

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=35+35-2=68$

Replacing we got

$t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31$

Part 2: P value

Since is a right tailed test the p value would be:

$p_v =P(t_{68}>4.31)=0.000022$

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

6 0

3 years ago

Can anybody solve this with explanation 12600 × 11/10 × 11/10