All categories

2 years ago

Which order is correct? 0.8. 1 2 3' 3 1. 0 -0.8, 2 1 1. 1 3 3 1 o 1 3. -0.8, 2 3 1 1 IN 1 -0.8 1

Mathematics

2 answers:

kari74 [83]2 years ago

5 0

I don’t know because I think you copied the question wrong

Phoenix [80]2 years ago

4 0

(A) just trust

ITs too good

You might be interested in

The amount of time it takes Renee to go grocery shopping is continuous and uniformly distributed between 18.5 minutes and 40.5 m

balandron [24]

Answer:

47.73% probability that it takes Renee at most 29 minutes to go grocery shopping

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

Uniformly distributed between 18.5 minutes and 40.5 minutes.

This means that $a = 18.5, b = 40.5$

What is the probability that it takes Renee at most 29 minutes to go grocery shopping

$P(X \leq 29) = \frac{29 - 18.5}{40.5 - 18.5} = 0.4773$

47.73% probability that it takes Renee at most 29 minutes to go grocery shopping

3 0

2 years ago

Hunter read a total of 22 books over 11 months. If Hunter has read 42 books so far, how

Mamont248 [21]

21 months. Hope this helps!

5 0

2 years ago

Can someone help me with this problem

scoray [572]

Answer:

For 7a its C i think And for 7b is 3:2

Step-by-step explanation:

hope this helps

6 0

3 years ago

*PLEASE ANSWER!! HURRY PLS*

atroni [7]

The answer to the question is c

5 0

2 years ago

Read 2 more answers

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

Which order is correct? 0.8. 1 2 3' 3 1. 0 -0.8, 2 1 1. 1 3 3 1 o 1 3. -0.8, 2 3 1 1 IN 1 -0.8 1​

Which order is correct? 0.8. 1 2 3' 3 1. 0 -0.8, 2 1 1. 1 3 3 1 o 1 3. -0.8, 2 3 1 1 IN 1 -0.8 1