The second constraint is the same as the objective function, so your problem boils down to finding integer solutions to
.. 3x1 +5x2 = 36

There are 3 solutions. They are (x1, x2) = (12, 0), (7, 3), (2, 6)

The value of the objective function there is (obviously) 36.

4 0

3 years ago

Let f(x) = 3x2 + x − 3 and g(x) = x2 − 5x + 1. Find f(x) − g(x)

tamaranim1 [39]

Answer:

Step-by-step explanation:

3 $x^{2}$ +x-3= $x^{2}$ - 5x

combine like terms

3 $x^{2}$ + $x^{2}$ = 4 $x^{2}$

x -5x = -4x

then combine 4 $x^{2}$ and -4x

6 0

3 years ago

What value of x satisfies the equation 5(x – 3) – 2(x + 1) = 4?

hjlf

Answer:

x = 7

Step-by-step explanation:

To solve:

Distribute 5 among everything inside the first parentheses. You'll get 5x - 15.

Next distribute -2 among everything in the second parentheses. You'll get

-2x - 2.

All together: 5x - 15 -2x - 2 = 4

Now combine like terms:

5x - 2x = 3x and -15 - 2 = - 17

All together: 3x - 17 = 4

Add 17 on both sides to get 21, and then divide both sides by 3. Answer is x = 7.

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Last, don't forget to check your work.

You can plug in 7 for x to get:

5(7 - 3) = 20

5 × 7 = 35

5 × -3 = -15

35 - 15 = 20

-2(7 + 1) = -16

-2 × 7 = -14

-2 × 1 = - 2

-14 -2 = -16

20 - 16 = 4

⬆⬆⬆Therefore this is correct.

Sorry this is a bit lengthy, but hope this helps :)

5 0

2 years ago

If the area of a rectangle with length (4x) is 4x2 + 12x, find the width.

8090 [49]

Answer:

The width of a rectangle is: w = x+3

Step-by-step explanation:

Given

The length of rectangle = l = 4x

The area of rectangle = A = 4x² + 12x

To determine

The width of rectangle = w = ?

We know that the formula of the area of the rectangle is

$A = wl$

substitute A = 4x² + 12x and l = 4x in the equation to determine the width w of the rectangle

4x² + 12x = w×4x

w = [4x² + 12x] / [4x]

Factor 4x² + 12x: 4x(x+3)

w = [ 4x(x+3) ] / [4x]

w = x+3

Therefore, the width of a rectangle is: w = x+3

3 0

3 years ago