If (x^2−1)/(x+1) = 3x + 5, then x + 3 = (A) -3 (B) -2 (C) 0 (D) 2 (E) 4
1 answer:
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Answer:
The given equation will have value less than 100 whenever the value of b is greater than 12.89
Step-by-step explanation:
For the given equation, p(b) = 520 × to have a value less than 100 we can establish inequality as:
p(b) < 100
or, 520 × < 100
or, ×
<
or, <
or, ㏒ ( ) < ㏒ (
)
or, b× ㏒ 0.88 < ㏒ ()
or, < b
or, 12.89 < b
Hence for the equation to have value less than 100, b must be greater than 12.89.