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Sati [7]
2 years ago
9

Triangle DEF has coordinates D (5,2), E (5,-2), and F(-4, 0). Which of the

Mathematics
1 answer:
andreev551 [17]2 years ago
4 0

Answer:

Well, I don't have further explanation to this question but I know the answer which is: The x-axis is the only line of symmetry

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2. Oranges cost $x per kilogram and apples cost $(x - 0.6) per kilogram. The total cost of 2 kg of oranges
Veseljchak [2.6K]
The value of x is 5.4 ( find the description in the picture)
5 0
2 years ago
I NEED HELP ASAPPP!!!! It’s urgentttttt!!!!
Akimi4 [234]

Answer: (x - 2)² + (y - 14)² = 1

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the idea of the circle formula.

Circle formula: (x - h)² + (y - k)² = r²

Center = (h, k)

Radius = r

If you are still confused, please refer to the attachment below for a graphical explanation.

<u>Solve:</u>

Center = (2, 14)

Radius = 1

<em>Given formula</em>

(x - h)² + (y - k)² = r²

<em>Substitute the value into the formula</em>

(x - 2)² + (y - 14)² = (1)²

<em>Simplify</em>

(x - 2)² + (y - 14)² = 1

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
What is the answer is it A. or B. or C. ?
nekit [7.7K]

Answer:

i believe its b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Seth invested a certain amount of money and got back an amount of $ 8400. If
kupik [55]

Answer:

$7700

Step-by-step explanation:

amount invested + interest = total

amount invested + 700 = 8400

Subtract 700 from both sides.

amount invested = 7700

Answer: $7700

5 0
2 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
3 years ago
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