Let that be x
ATQ
Arrange accordingly to work backwards(Every thing is reversed)
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I'm sorry you need to be more clear I don't understand the question.
<h2>Answer:</h2><h3>W = 5</h3><h3>Step-by-step explanation:</h3><h3>Simplify the brackets. </h3><h3>-2x^2 + wx - 4 - x^2 - 5x - 6 = -3x^2 - 10</h3><h3>Then simplify (-2x^2 + wx - 4 - x^2 - 5x - 6) to </h3><h3>( -3x^2 + wx - 10 - 5x)</h3><h3>This will give you 3x^2 + wx - 10 - 5x = -3x^2 - 10. </h3><h3>Now you need to cancel out -3x^2 on both sides. </h3><h3>wx - 10 - 5x = -10</h3><h3>Then cancel out -10 from both sides. </h3><h3>wx - 5x = 0</h3><h3>Now factor out the common term. (x) </h3><h3>w - 5 = 0.</h3><h3>giving you the answer w = 5. </h3><h3 /><h3 /><h3>welcome. *yeets*</h3>
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards.
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards.
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x.
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
=> Area, A
= 2x (y1 - y2)
= 2x (18 - x^2 - 2x^2 + 9)
= 2x (27 - 3x^2)
= 54x - 6x^3
For area to be maximum, dA/dx = 0 and d²A/dx² < 0
=> 54 - 18x^2 = 0
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants)
d²A/dx² = - 36x < 0 for x = √3
=> maximum area
= 54(√3) - 6(√3)^3
= 54√3 - 18√3
= 36√3.
6.2:
fraction: .2 = 0.20 = 20/100
fraction: 6 20/100
Word form: six point two
two and five hundredths
fraction: 2 5/100
decimal form 2.05
hope this helps
