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Sveta_85 [38]
3 years ago
7

Elaborate on the difference in natural occurrences between fission and fusion reactions. A) Neither fission nor fusion reactions

naturally occur on earth or outer space. B) Fission reactions do not naturally occur while fusion reactions occur in the stars. C) Both fission and fusion reactions naturally occur in the pressure of the earth's core. D) Fusion reactions do not naturally occur while fission reactions occur in the volcanoes.
Chemistry
2 answers:
vazorg [7]3 years ago
8 0
<span>Okay then I would go with choice B since fusion takes place in the sun which is a giant star.</span>
11111nata11111 [884]3 years ago
7 0

Answer: Option 'B' is correct.

Explanation:

Nuclear fission means the splitting of larger atoms into two or more smaller atoms whereas Nuclear fusion means the splitting of two or more atoms into larger atoms.

Nuclear fission does not occur naturally but nuclear fusion occurs in stars etc.

So, only statement is correct regarding the difference in natural occurrences between fission and fusion.

Hence, Option 'B' is correct.

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Read 2 more answers
How many molecules are in 85g of silver nitrate?
maksim [4K]
<h3>Answer:</h3>

3.0 × 10²³ molecules AgNO₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Writing Compounds
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

85 g AgNO₃ (silver nitrate)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 85 \ g \ AgNO_3(\frac{1 \ mol \ AgNO_3}{169.88 \ g \ AgNO_3})(\frac{6.022 \cdot 10^{23} \ molecules \ AgNO_3}{1 \ mol \ AgNO_3})
  2. Multiply/Divide:                                                                                                \displaystyle 3.01313 \cdot 10^{23} \ molecules \ AgNO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.01313 × 10²³ molecules AgNO₃ ≈ 3.0 × 10²³ molecules AgNO₃

6 0
3 years ago
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