I’m just letting you know this is really easy you just calculate the molar mass of each compound and divide the amount of the compound (grams) by the molecular Mass
Answer:
Explanation:
The stoichiometry for this reaction is
The rate for this reaction can be written as
![-r_{NO_2}=-\frac{d\left[NO_2\right]}{dt}=\frac{(0.01-0.008)M}{100s}=2\times{10}^{-5}\frac{M}{s}](https://tex.z-dn.net/?f=-r_%7BNO_2%7D%3D-%5Cfrac%7Bd%5Cleft%5BNO_2%5Cright%5D%7D%7Bdt%7D%3D%5Cfrac%7B%280.01-0.008%29M%7D%7B100s%7D%3D2%5Ctimes%7B10%7D%5E%7B-5%7D%5Cfrac%7BM%7D%7Bs%7D)
This rate of disappearence of 
can be realated to the rate of appearence of 
as follows (the coefficients of each compound are defined by the stoichiometry of the reaction)
Balanced chemical reaction: 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g).
KOH is inorganic compound p<span>otassium hydroxide, a strong base.
H</span>₂ is hydrogen gas.
In balanced chemical reaction number of atoms on both side of chemical reaction must be same. There are two potassium atoms, four hydrogen atoms and two oxygen atoms on both side of reaction.
Neutrons are neutral Electron are negative and protons are positive
The equation is as follows:
Cyclohexane (C6H12) ⇔ Methyl cyclopentane (C6H12)
The equilibrium constant Kc = 0.143 >>> (1)
Qc is the reaction quotient
where; If Q = K >>>> No shift left or right >>> (2)
Q > K >>>> Reaction shifts left >>> (3)
Q < K >>>> Reaction shifts right >>> (4)
And in our equation; Q = 0.3 / 0.4 = 0.75 >>> (5)
From (1), (3) and (5), Q > Kc
∴ the reaction shifts left
