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mrs_skeptik [129]
3 years ago
12

Help me on this questionnnnn kinda confusing

Mathematics
1 answer:
valina [46]3 years ago
5 0
The first one because it’s 4 pounds unless it’s one piece of meat that just wieghs four pounds
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What is the sum of 2x^2-x and -x-2x^2-2
Lorico [155]
<h2><em>Answer:</em></h2><h3><em>-</em><em>2</em><em>x</em><em>-</em><em>2</em></h3>

<em>solution \\  {2x}^{2}  - x + ( - x -  {2x}^{2}  - 2) \\  =  {2x}^{2}  - x  - x -  {2x}^{2}  - 2 \\  =  {2x}^{2}  -  {2x}^{2}  - x - x - 2 \\  =  - 2x - 2</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

5 0
3 years ago
Read 2 more answers
А A<br> B<br> D<br> If m_ABD = 64°, and mZCBD = 30°,<br> then m ABC = [?]°
Zina [86]

Answer:

34 degrees

Step-by-step explanation:

If ABD = 64, and CBD is 30, we can use PWP( Part Whole Postulate)

Step 1.CBD + ABC = ABD

Step 2. Substitute

30 + ABC = 64

Step 3. Isolate ABC

34 = ABC

ABC is 34 degrees

5 0
3 years ago
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What’s the answer<br> ??????????????????????????????????
LenKa [72]

It’s 8/4 which equals two

5 0
4 years ago
The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.9 days and a standard de
FrozenT [24]
The 70th percentile is the same as the cutoff recovery time t such that every point above this time falls in the longest 30%, i.e.

\mathbb P(X>t)=0.30

Transform to the standard normal distribution:

\mathbb P\left(\dfrac{X-5.9}{2.5}>\dfrac{t-5.9}{2.5}\right)=\mathbb P(Z>t^*)

where t^* is the z-score corresponding to the cutoff time t, which is approximately t^*\approx0.5244. Solve for t:

t^*\approx0.5244=\dfrac{t-5.9}{2.5}\implies t\approx7.21\text{ days}
6 0
4 years ago
Help help help help help​
wariber [46]

Answer:

Step-by-step explanation:

1) (-6 , 2) ; (3 , -5)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

         = \frac{-5-2}{3-[-6]}\\\\= \frac{-5-2}{3+6}\\\\= \frac{-7}{9}\\

m = -7/9 ; (-6 , 2)

y - y₁ = m(x -x₁)

y - 2 = (-7/9)(x - [-6])

y - 2 = \frac{-7}{9}(x + 6)\\\\y -2 = \frac{-7}{9}x + \frac{-7}{9}*6\\\\y - 2 = \frac{-7}{9}x - \frac{7*2}{3}\\\\  y = \frac{-7}{9}x - \frac{14}{3} + 2\\\\y = \frac{-7}{9}x -\frac{14}{3} + \frac{2*3}{1*3}\\\\y = \frac{-7}{9}x - \frac{14}{3} + \frac{6}{3}\\\\y = \frac{-7}{9}x - \frac{8}{3}

2) (3 , -4) ; m= 3

y - y_{1} = m(x - x_{1})

y - [-4] = 3(x - 3)

y + 4 = 3x - 3*3

y + 4 = 3x  - 9

     y = 3x - 9 - 4

Ans: y = 3x - 13

3) m = 2 ; y-intercept (b) = 3/2

     y = mx + b

  Ans: y = 2x + (3/2)

4) (-1, 3 ) ;  (2 , 0)

Slope = \frac{0 - 3}{2-[-1]}

         = \frac{-3}{2+1}\\\\= \frac{-3}{3}\\\\= 1

m = 1; ( -1 , 3)

y - 3 = 1(x -[-1])

y - 3 = 1(x + 1)

y - 3 = x + 1

    y = x + 1 + 3

  Ans: y = x + 4

5)(2, 1) ;m = -3

y - 1 = (-3)(x - 2)

y - 1 = -3x + 6

   y = -3x + 6 +1

Ans: y = -3x + 7

5 0
3 years ago
Read 2 more answers
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