Please please help me I’m so lost
1 answer:
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Time for entire trip = 2d/30 hours
Time for first part of trip = d/60.
Time for second part of trip, is given by:
Therefore the speed during the second distance d is 20 mi/h.
Time for first part of trip = d/60.
Time for second part of trip, is given by:
Therefore the speed during the second distance d is 20 mi/h.
Answer:
See answer and graph below
Step-by-step explanation:
∬Ry2x2+y2dA
=∫Ry.2x.2+y.2dA
=A(2y+4Ryx)+c
=∫Ry.2x.2+y.2dA
Integral of a constant ∫pdx=px
=(2x+2.2Ryx)A
=A(2y+4Ryx)
=A(2y+4Ryx)+c
The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2
