As a neutral lithium atom contains 3 protons and its elemental charge is given as $1.602 \times 10^{-19} C$ . Hence, we will calculate its number of moles as follows.

Moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.7 \times 1000 g}{7 g/mol}$

= 100 mol

According to mole concept, there are $6.023 \times 10^{23}$ atoms present in 1 mole. So, in 100 mol we will calculate the number of atoms as follows.

No. of atoms = $100 \times 6.023 \times 10^{23}$

= $6.023 \times 10^{25}$ atoms

Since, it is given that charge on 1 atom is as follows.

$3 \times 1.602 \times 10^{-19}C$

= $4.806 \times 10^{-19}C$

Therefore, charge present on $6.023 \times 10^{25}$ atoms will be calculated as follows.

$6.023 \times 10^{25} atoms \times 4.806 \times 10^{-19} C$

$28.95 \times 10^{6}C$

Thus, we can conclude that a positive charge of $28.95 \times 10^{6}C$ is in 0.7 kg of lithium.

3 0

3 years ago

Which ocean surface current travels north along the eastern United States coast? A. Labrador current B. Canaries current C. Gulf

Marina86 [1]

It is answer C
there ya go friend

8 0

3 years ago

Read 2 more answers

A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10

Alex17521 [72]

Answer:

Mass of P4O6=103.4

P4O10=133.48

Explanation:

Balanced reaction is:

8P +8 $O_{2}$ ⇒ $P_{4} O_{6}$ + $P_{4} O_{10}$

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P= $\frac{117.9}{31}$ =3.80

Moles of $O_{2}$ = $\frac{117.9}{31}$ =3.80

No. of moles of formed product are equal and is $\frac{1}{8}$ th of mole of any of reactant.

Thus weight of $P_{4} O_{6}$ = $\frac{3.80}{8}$ ×220 ≈103.41

weight of $P_{4} O_{10}$ = $\frac{3.80}{8}$ ×284 ≈133.48

4 0

3 years ago

PLEASE HELP! ONLY SERIOUS ANSWERS! I APPRECIATE ANYTHING!! 30PTS!!!

xenn [34]

1 is b 2 is a 3 is d 4 is a 5 is c

5 0

3 years ago