Answer: the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa
Explanation:
The question requires us to calculate the pressure, in kPa, connsidering the following information:
<em>number of moles = n = 4.20mol</em>
<em>volume of gas = V = 15.0L</em>
<em>temperature of gas = T = 280.0 K</em>
We can use the equation of ideal gases to calculate the pressure of the gas, as shown by the rearranged equation below:

Since the volume was given in L and the question requires us to calculate the pressure in kPa, we can use R in units of L.Pa/K.mol:
<em>R = 8314.46 L.Pa/K.mol</em>
Applying the values given by the question to the rearranged equation above, we'll have:

Therefore, the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa.
Answer:
Two moles of KClO3 decompose to form 5 moles of product.
Moles=concentration x volume. 1.5/1000 multiply 0.450 = 6.75x10^-4
To find the mass of fecl3, we have the formula, mass=moles x molar mass. 6.75x10^-4 x (55.8+35.5 x 3). = 0.1096g
Not sure tho if i did it right