Find the perimeter of the triangle

Mathematics

1 answer:

zloy xaker [14]3 years ago

5 0

Answer:

=136

Step-by-step explanation:

Lets solve the triangle using the sine formula.

c/sine C=a/sine A

C= 180-(72+16)

=92°

61/Sin 92=a/sin 72

a=(61 sin 72)/sin 92

=58.0

Solving for b:

c/sin C= b/Sin B

61/sin 92= b/Sin 16

b=(61 Sin 16)/Sin 92

=16.82

Perimeter = 61 +58+ 16.82 = 135.82

Answer =136 to the nearest whole number.

You might be interested in

If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b

Readme [11.4K]

Answer:

Exact distance = $90\sqrt{2}$ feet
Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

$a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\$

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0

2 years ago

Equal set is equivalent set but equivalent set not need equal set? why

nasty-shy [4]

Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets

6 0

3 years ago

PLEASE HELP I WILL MARK BRAINLIST!!

marshall27 [118]

14: $\frac{1}{2} = \frac{8}{1}$ $\frac{x}{y} = \frac{56}{1}$