Answer:
15.33cm
Step-by-step explanation:
when you try to draw out this figure, satisfying the fact that Ad and Ac are both straight lines. you find the ultimately it forms a right-angled triangle with sides AC and AD and hypotenuse CD.
Now, you may use Pythagoras theorem to solve:
AC^2 + AD^2 = CD^2
12.3^2 + 9.15^2 = CD^2
CD^2 = 235.0125
CD = square root of 235.0125 = 15.33cm
Hope this helps
See attachments for the answers.
Answer:
Area of the shaded region = 23.33 in²
Step-by-step explanation:
Area of a sector = 
Where θ = Central angle subtended by an arc
r = radius of the circle
Area of the sector BCD = 
= 52.36 in²
Area of equilateral triangle BCD = 
= 
=
in²
= 43.30 in²
Area of the shaded portion in ΔBCD = 52.36 - 43.3
= 9.06 in²
Area of sector CAD = 
= 39.27 in²
Area of right triangle CAD = 
= 
=
= 25 in²
Area of the shaded part in the ΔACD = 39.27 - 25
= 14.27 in²
Area of the shaded part of the figure = 9.06 + 14.27
= 23.33 in²
The place value of 1 is hundred thousands.
If I’m not wrong I think it’s x+1