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lozanna [386]
3 years ago
11

Which of the following inequalities matches the graph?

Mathematics
1 answer:
masha68 [24]3 years ago
7 0
I believe it is the last one y>-1
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What value could be added to 2/15 to make the sum greater than 1/2
olya-2409 [2.1K]
Anything greater than or equal to 6/15
8 0
4 years ago
Write a function rule for the given graph identify the value of y when x=12 <br> write out the steps
joja [24]

Answer:

y=8

Step-by-step explanation:

We need to find the equation for the line.

The first step is to find the slope

We need 2 points  (0,2) (2,3)


slope = (y2-y1)/(x2-x1)

          = (3-2)/(2-0)

          = 1/2

We know the y intercept ( where it crosses the y axis)  at 2

Lets use the slope intercept form of the line

y= mx+b

y = 1/2 x+2

If we want to find the value of y when x =12 , substitute the value of x=12

y =1/2 * 12 +2

y = 6+2

y=8

5 0
3 years ago
A bin contains 72 light bulbs of which 10 are defective. If 5 light bulbs are randomly selected from the bin with replacement, f
Serhud [2]

Answer:

0.4735

Step-by-step explanation:

10 defective, 62 not defective

P(good) = 62/72 = 31/36

All 5 good:

(31/36)⁵ = 0.4734738145

7 0
3 years ago
Pls help me with this
katrin [286]

Answer:

f(X)=2x is the correct answer

3 0
3 years ago
What is the probability that a data value in a normal distribution is between a
Vsevolod [243]
<h3>Answer:   choice A) 55.3%</h3>

====================================================

Explanation:

Use a Z table found in the back of your book to find that

P(Z < -0.41) = 0.3409

P(Z < 1.25) = 0.8944

So,

P(-0.41 < Z  < 1.25) = P(Z < 1.25) - P(Z < -0.41)

P(-0.41 < Z  < 1.25) = 0.8944 - 0.3409

P(-0.41 < Z  < 1.25) = 0.5535

Now convert this to a percentage by multiplying by 100, which is the same as moving the decimal point over 2 places

0.5535 ---> 55.35%

Round this to the nearest tenth of a percent. You could argue that 55.35% rounds to either 55.3% or 55.4% since that last digit is a 5. I'm going with 55.3% since 55.4% isn't listed as an answer choice. The table I used only lists approximate values, so there is likely some rounding error somewhere. When I used my TI83 (see image below) I got roughly 0.5534 which is fairly close to 0.5535. If you want to use your TI83 or TI84 calculator, then the normalcdf function can be found by pressing the yellow "2ND" button (top left corner) and then pressing the VARS key (3rd row from the top, just to the left of the CLEAR key).

6 0
4 years ago
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