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From the figure, segment QP is in the ray RP and RP contains N and Q in between
so from the options, the two rays will be : ray QP and ray NP
For SU :
segment SU is in the ray RU and RU contains S and T in between,
so from the options again, the two rays will be : ray RU and ray SU
Answer:
Option b is correct.
Linear function ;
y =2x
Step-by-step explanation:
The formula y=f(x)=mx +c ......[1] is said to be a linear function. That means the graph of this function will be a straight line on the (x, y) plane, where m represents slope and b is the y-intercepts.
Consider any points from the table;
(1, 2) and (2, 4)
substitute these point in [1] we get;
for (1, 2)
⇒x = 1 and f(x) = 2 we have
2 = m + c
or
c = 2- m ......[1]
for (2, 4) we have;
4 = 2m + c .....[2]
Now, substitute equation [1] into [2] we get;
4 = 2m + 2 -m
Combine like terms;
4 = m + 2
Subtract 2 from both sides we get;
4 -2 = m +2 -2
Simplify:
2 = m or
m = 2
Substitute the value of m = 2 in [1] to solve for c;
c = 2 -2 = 0
c =0
⇒ y = 2x +0
y = 2x
therefore, the data in the table represents the Linear function and a possible formula for the linear function is; y = 2x
Answer:
Option 1: 1430p + 2200 = -4001
Step-by-step explanation:
Given that:
1.43p + 2.2 = -4.001
We can replace:
1.43p by 1430p * 10^-3
2.2 by 2200 * 10^-3
-4.001 by -4001* 10^-3
So the equation will become:
1430p * 10^-3 + 2200* 10^-3 = -4001 * 10^-3
Taking 10^-3 common from both side
(1430p + 2200)* 10^-3 = -4001 * 10^-3
Cancelling 10^-3 from both sides we get:
1430p + 2200 = -4001
Answer:
Distance traveled in one second by car=374/17=22meters
Step-by-step explanation:
Distance traveled by bus in one second=414.23=18 meters. Car travels faster.It travels 4 meter more in one second than Bus.
