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2 years ago

15

I added pics cause it’s 2 in the morning.. I’m having back pain, thigh pain, cramps EVERYWHERE.. headache and just finished baby

sitting my baby brother.. help a gurl out please

1 answer:

liberstina [14]2 years ago

5 0

Answer:

$\frac{1}{4^2}$

Step-by-step explanation:

$4^6*4^{-8}\\\\=\frac{4^6}{4^{8} }\\\\ =4^{-2} \\\\=\frac{1}{4^2}$

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Find the directional derivative of f(x, y, z) = xy + yz + zx at p(1, −1, 7) in the direction from p to q(2, 4, 5). duf(1, −1, 7)

oksian1 [2.3K]

$f(x,y,z)=xy+yz+zx$

$\implies\nabla f(x,y,z)=(y+z,x+z,y+x)$

$\vec{pq}=\mathbf q-\mathbf p=(2-1,4-(-1),5-7)=(1,5,-2)$

$\|\vec{pq}\|=\sqrt{30}$

$D_{\vec{pq}}f(1,-1,7)=\nabla f(1,-1,7)\cdot\dfrac{(1,5,-2)}{\sqrt{30}}=\dfrac{(6,8,0)\cdot(1,5,-2)}{\sqrt{30}}=\dfrac{46}{\sqrt{30}}$

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3 years ago

What does x equal if 8x - 4 equals 4x plus 1

postnew [5]

4x=5 Answer: so 5/4

Step-by-step explanation: 8x-4 = 4x + 1

add like terms so 4x=5 then divide

8 0

3 years ago

Read 2 more answers

Bag A: Two thirds of the candies are yellow. What portion of the candies is green

dalvyx [7]

Answer: $\frac{1}{3}$ proportion of candies are green.

Solution:

In bag A, $\frac{2}{3}$ candies are yellow.

$\frac{2}{3}$ this proportion shows ratio of favorable over total candies.

Here numerator number is 2.

So, Total number of yellow candies should be 2x

Total number of candies in Bag A would be 3x

Number of green candies in bag A = 3x-2x = x

Now we find the portion of green candies in bag A

$\therefore,$ $\frac{x}{3x}$

$\frac{1}{3}$ portion of candies are green in bag A

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2 years ago

OLga [1]

The answer would be. B) 2V5 units

6 0

3 years ago

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Solve the inequality algebraically. Write the solution in interval notation.<br> |9x + 10| < 15

viva [34]

The given inequality is

$| 9x+ 10 |$

First we need to remove the absolute sign , and when we do so , we will get a compound inequality, that is

$-15< 9x+10 < 15$

To solve for x, first we need to get rid of 10. and for that, we have to do subtraction

$-15-10$

Now we need to get rid of 9, and for that, we do division

$\frac{-25}{9}< x< \frac{5}{9}$

So the required solution is

$( \frac{-25}{9} , \frac{5}{9})$

5 0

3 years ago