-.0336
-.14*.12 = -.0168
.14*.12 = .0168
-.0168-.0168=-.0336
If you slice it down the dotted line, you will have a rectangle with a width of 2 and a length of 4.
The area of the rectangle will be 8 square centimeters.
2 x 4 = 8
Answer:
![B)\,\,A^{-1}=\left[\begin{array}{ccc}7&-1&-1\\-3&1&0\\-3&0&1\end{array}\right]](https://tex.z-dn.net/?f=B%29%5C%2C%5C%2CA%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-1%26-1%5C%5C-3%261%260%5C%5C-3%260%261%5Cend%7Barray%7D%5Cright%5D%20)
Step-by-step explanation:
Expanding with first row
![det(A) = \left\Bigg|\begin{array}{ccc}1&1&1\\3&4&3\\3&3&4\end{array}\right\Bigg|\\\\\\det(A)= (1)\left\Big|\begin{array}{cc}4&3\\3&4\end{array}\right\Big|-(1)\left\Big|\begin{array}{cc}3&3\\3&4\end{array}\right\Big|+(1)\left\Big|\begin{array}{cc}3&4\\3&3\end{array}\right\Big|\\\\det(A)=1[16-9]-1[12-9]+1[9-12]\\\\det(A)=7-3-3\\\\det(A)=1](https://tex.z-dn.net/?f=det%28A%29%20%3D%20%5Cleft%5CBigg%7C%5Cbegin%7Barray%7D%7Bccc%7D1%261%261%5C%5C3%264%263%5C%5C3%263%264%5Cend%7Barray%7D%5Cright%5CBigg%7C%5C%5C%5C%5C%5C%5Cdet%28A%29%3D%20%281%29%5Cleft%5CBig%7C%5Cbegin%7Barray%7D%7Bcc%7D4%263%5C%5C3%264%5Cend%7Barray%7D%5Cright%5CBig%7C-%281%29%5Cleft%5CBig%7C%5Cbegin%7Barray%7D%7Bcc%7D3%263%5C%5C3%264%5Cend%7Barray%7D%5Cright%5CBig%7C%2B%281%29%5Cleft%5CBig%7C%5Cbegin%7Barray%7D%7Bcc%7D3%264%5C%5C3%263%5Cend%7Barray%7D%5Cright%5CBig%7C%5C%5C%5C%5Cdet%28A%29%3D1%5B16-9%5D-1%5B12-9%5D%2B1%5B9-12%5D%5C%5C%5C%5Cdet%28A%29%3D7-3-3%5C%5C%5C%5Cdet%28A%29%3D1)
To find inverse we first find cofactor matrix
Cofactor matrix is
![C=\left[\begin{array}{ccc}7&-3&3\\-1&1&0\\-1&0&1\end{array}\right] \\\\Adj(A)=C^{T}\\\\Adj(A)=\left[\begin{array}{ccc}7&-1&-1\\-3&1&0\\-3&0&1\end{array}\right] \\\\\\A^{-1}=\frac{adj(A)}{det(A)}\\\\A^{-1}=\frac{\left[\begin{array}{ccc}7&-1&-1\\-3&1&0\\-3&0&1\end{array}\right] }{1}\\\\A^{-1}=\left[\begin{array}{ccc}7&-1&-1\\-3&1&0\\-3&0&1\end{array}\right]](https://tex.z-dn.net/?f=C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-3%263%5C%5C-1%261%260%5C%5C-1%260%261%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CAdj%28A%29%3DC%5E%7BT%7D%5C%5C%5C%5CAdj%28A%29%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-1%26-1%5C%5C-3%261%260%5C%5C-3%260%261%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5CA%5E%7B-1%7D%3D%5Cfrac%7Badj%28A%29%7D%7Bdet%28A%29%7D%5C%5C%5C%5CA%5E%7B-1%7D%3D%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-1%26-1%5C%5C-3%261%260%5C%5C-3%260%261%5Cend%7Barray%7D%5Cright%5D%20%7D%7B1%7D%5C%5C%5C%5CA%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%26-1%26-1%5C%5C-3%261%260%5C%5C-3%260%261%5Cend%7Barray%7D%5Cright%5D)
D and F are not equivalent to ax+bx+ac+bc+
Answer: y = 3x - 5
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
c = intercept
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line is
y = -1/3x + 2
Comparing with the slope intercept form, slope = - 1/3
If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line. Therefore, the slope of the line passing through
(2, 1) is 3/1 = 3
To determine the intercept, we would substitute m = 3, x = 2 and y = 1 into y = mx + c. It becomes
1 = 3 × 2 + c = 6 + c
c = 1 - 6 = - 5
The equation becomes
y = 3x - 5
