Answer:
Option c
Step-by-step explanation:
A system of equations are given to us. And we need to solve them . The given system is
We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .
We got two values of x as 0 & 2 . Alternatively substituting these values we have ,
Thefore the required answer is ,
Answer:
The number of classrooms needed to accommodate all the classes is 22.
Step-by-step explanation:
[text}N_{classes} / N_{time slots} = N_{classrooms}[/text]
281 / 13 = 21.6; the number of classrooms needed to accommodate all the classes is 22.
To calculate the number of classrooms that you need to accommodate 281 different classes in 13 time slots, you have to divide the number of classes (281) by the number of time slots (13). The result is 21.6 classrooms needed. However, because you cannot have a class to a 0.6 classroom, you have to round up to 22.
The answer is P=S23 because you add them all Isaac nut on didn’t get apples
Let ones digit = z
Let tens digit = y
Let hundreds digit = x
Then three digit number xyz will be equivalent to (100x+10y+z)
If we reverse the digits then new number zyx will be equivalent to (100z+10y+x)
2(100x+10y+z)=(100z+10y+x)+1
200x+20y+2z=100z+10y+x+1
199x+10y-98z-1=0
There are no more conditions given so that we can use them to minimize calculation in order to find the answer.
So now we have only choice to plug random numbers for x,y,z which can vary from 0 to 9.
Working as explained above gives x=3, y=9, z=7 is satisfying the above equation.
Hence required number is 397.