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valentina_108 [34]
3 years ago
10

Use the following information to answer the question. The mean age of lead actresses from the top ten grossing movies of 2010 wa

s 29.6 years with a standard deviation of 6.35 years. Assume the distribution of the actresses' ages is approximately unimodal and symmetric. Between what two values would you expect to find about 95% of the lead actresses ages
Mathematics
1 answer:
Alex787 [66]3 years ago
4 0

Answer:

You should expect to find about 95% of the lead actresses ages between 16.9 years and 42.3 years.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 29.6 years, Standard deviation = 6.35 years.

Between what two values would you expect to find about 95% of the lead actresses ages

By the Empirical Rule, within 2 standard deviations of the mean. So

29.6 - 2*6.35 = 16.9 years

29.6 + 2*6.35 = 42.3 years

You should expect to find about 95% of the lead actresses ages between 16.9 years and 42.3 years.

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A shepherd is paid rs.2400 for gazing 18 cows for 5 weeks.How much will be paid for gazing 20 cows for 8 weeks?
lys-0071 [83]

Answer:

Rs. 4266.67(approx) will be paid for gazing 20 cows for 8 weeks.

Explanation:

A shepherd is paid rs. 2400 for gazing 18 cows for 5 weeks .

⇒ Number of money paid for gazing 1 cow for 1 week is, \frac{2400}{18\times 5} =\frac{400}{15}= \frac{80}{3}

then,

for gazing 20 cows for 8 weeks is=  Rs. \frac{80}{3}\times (20\times 8)

Therefore, the amount paid for gazing 20 cows for 8 weeks is, \frac{80 \times 160}{3} = \frac{12800}{3} = Rs. 4266.66667 or Rs. 4266.67(approx)

7 0
3 years ago
n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,
Nitella [24]

Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

A = Pe^{rt}

Where,

P = initial population,

r = growth rate per period,

t = number of periods,

Given,

The population in 2000, P = 2,400,

Growth rate per year = 1.68% = 0.0168,

Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

A=2400 e^{0.0168\times 20}

=2400 e^{0.336}

= 3358.4136

\approx 3358

6 0
3 years ago
What would this be? Thanks for helping!
igor_vitrenko [27]

Answer:

if I remember correctly it would be a triangle.

6 0
2 years ago
Read 2 more answers
I need help wit one & two please help
seropon [69]

23 is less than 25 which means it's closer to 20, so you would round it down to 20. 1.75 is over 0.50, 1/2, so you would round it up to 2. If you multiply 2 and 20 you would get 40.

Number two gets the same explanation just with different numbers.

3 0
3 years ago
By what number should ( -5)(-1) be multiplied so that the product may be equal to (10)(-1)​
Rudik [331]
Answer: -2

(-5)(-1)x=(10)(-1)
5x = -10
x = -2
7 0
2 years ago
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