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valentina_108 [34]
2 years ago
10

Use the following information to answer the question. The mean age of lead actresses from the top ten grossing movies of 2010 wa

s 29.6 years with a standard deviation of 6.35 years. Assume the distribution of the actresses' ages is approximately unimodal and symmetric. Between what two values would you expect to find about 95% of the lead actresses ages
Mathematics
1 answer:
Alex787 [66]2 years ago
4 0

Answer:

You should expect to find about 95% of the lead actresses ages between 16.9 years and 42.3 years.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 29.6 years, Standard deviation = 6.35 years.

Between what two values would you expect to find about 95% of the lead actresses ages

By the Empirical Rule, within 2 standard deviations of the mean. So

29.6 - 2*6.35 = 16.9 years

29.6 + 2*6.35 = 42.3 years

You should expect to find about 95% of the lead actresses ages between 16.9 years and 42.3 years.

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xenn [34]

Answer:

$0.30 x 4= $1.20

$3.00 divided by $1.20= $1.80

Step-by-step explanation:

I hope this is what you were looking for

7 0
3 years ago
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Find the quadratic function that fits the following data. which one function fits.
Oksana_A [137]

Answer:

C

Step-by-step explanation:

The general rule for the quadratic function is

y=ax^2+bx+c

Use the data from the table:

y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c

We get the system of three equations:

\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.

Subtract these equations:

\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.

From the first equation

b=-120a

Substitute it into the second equation:

5600a+40\cdot (-120a)=70\Rightarrow 800a=70,\\ \\ a=\dfrac{7}{80},\\ \\ b=-120\cdot \dfrac{7}{80}=-\dfrac{21}{2}=-10.5

So,

2500\cdot \dfrac{7}{80}+50\cdot (-10.5)+c=130\Rightarrow 218.75-525+c=130\\ \\c=130-218.75+525=436.25

The quadratic function is

y=\dfrac{7}{80}x^2-10.5x+436.25\\ \\y=0.0875x^2-10.5x+436.25

4 0
3 years ago
The surface area of a typical classroom floor is closest to______.
avanturin [10]
Answer would be C. Why A would be incorrect: 100m^2 is 100m × 100 m. That would be as big as a football field. Why B would be incorrect: 1cm^2 is 1cm × 1cm. You can use a regular 15 cm to measure a piece of paper with the length of 1cm each side. Why C would be correct: 1m^2 = 1m × 1m and it is also equals to 60cm × 60 cm. A 1 meter ruler = 60 cm = 4 times of your average 15 cm ruler. So, it is reasonable that a classroom is 10m by 10m in length and breadth. Why D would be incorrect: The same explanation applies to here as well. Things that can be measured with 1m × 1m is a square table so your classroom can't be that small to fit an average of 30 to 40 students in there. I hope my explanations were detailed and easy to understand. :)
4 0
2 years ago
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10110, written in base 10 is
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A fake link ........................
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Lin borrowed 950 for a new laptop. She will pay $25,80 each month for the next 48 months (2 years). Find the amount of
icang [17]

Answer:

288,40 $

Step-by-step explanation:

25,80$ / month * 48 months = 1238,40$ total payment.

1238,40$ - 950$ (borrowed) = 288,40 $ payed in interest.

4 0
2 years ago
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