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3 years ago

Determine whether each equation represents exponential growth or decay y=16.5(1.025)^(1/x)

Mathematics

1 answer:

asambeis [7]3 years ago

8 0

That equation would be an exponential decay because as x gets bigger, the f(x) gets smaller.

i.e

y=16.5(1.025)^(1/1) = 16.9 rounded

y=16.5(1.025)^(1/2) = 8.5 rounded

y=16.5(1.025)^(1/3) = 5.6 rounded

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BRAINLIEST TO WHOEVER ANSWERS!!

tiny-mole [99]

Answer:

y = 10 + 2.50h

$25

Step-by-step explanation:

first the equation is written as such because she pays $10 no matter how many hours she rides. She also pays 2.50 for each hour so use h as the variable to define number of hours she rides the bike.

since equation is y = 10 +2.50h

and h = 6 hours, substitute and find the total cost

y = 10 + 2.50(6)

= 10 + 15

= $25

6 0

2 years ago

A random sample of 35 undergraduate students who completed two years of college were asked to take a basic mathematics test. The

disa [49]

Answer:

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

Step-by-step explanation:

The null and alternative hypothesis are given by

H0: σ₁²= σ₂² against Ha: σ₁² ≠ σ₂²

Confidence interval for the population mean difference is given by

(x`1- x`2) ± t √S²(1/n1 + 1/n2)

Where S ²= (n1-1)S₁² + S²₂(n2-1)/n1+n2-2

Critical value of t with n1+n2-2= 50+ 35-2= 83 will be -1.633

Now calculating

S ²=34* (12.8)²+ (14.6)²*49/83= 192.96

Now putting the values in the t- test

(75.1 -72.1) ± 1.633 √ 192.96(1/35 +1/50)

=3 ± 5.09

=-2.09, 8.09 is the 90 % confidence interval for the difference

The 90 % confidence limits are (-2.09, 8.09).

Since the calculated values do not lie in the critical region we accept our null hypothesis.

5 0

3 years ago

Suppose that you work for the child social services agency in your county. Your job is to investigate instances of possible chil

True [87]

Answer:

Null hypothesis: ∪ = No possible child abuse or neglect

Alternative hypothesis: Uₐ = Possible child abuse or neglect

Step-by-step explanation:

Null hypothesis: ∪ = No possible child abuse or neglect

Alternative hypothesis: Uₐ = Possible child abuse or neglect

A type I error occurs when you reject the null hypothesis when it is true. In this situation, a type I error occurs when you conclude on possible child neglect or abuse and place the child in protective custody

A type II error occurs when you accept the null hypothesis when it is false. In this instance, a type II error occurs when you conclude on no possible child abuse or neglect when there is and fail to remove the child from the home.

In this case, the type II error is the more serious error. Failure to remove the child when there is possible child abuse or neglect will lead to more detrimental effect. Although, the type I error is also serious, it is not so detrimental as the type II error.

5 0

3 years ago

0.965 x 102 help me plz

ValentinkaMS [17]

98.43

May nilbin be with you

5 0

2 years ago

Read 2 more answers

Dividing a decimals by a decimal like 2.4 divid by 16.4

aksik [14]

Well 2.4/ 16.4 is 6.9, but idk if that is what u were asking for

5 0

3 years ago