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Nikolay [14]
3 years ago
8

A new physical therapy is being tested in an experimental setting to see if

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

Control Group.

Step-by-step explanation:

A control group, in research, is a group that is not experimented by the researchers in an experiment. A control group is the opposite of an experimental group, on which the independent variable is performed. In other words, an independent variable is held on 'control' in control group.

<u>In the given scenario, the experiment is being performed to test a new physical therapy. To do so, the researchers divided the group in three groups, in which, one group did not receive any treatment; the treatment is held on 'control' in this group.</u>

So, according to the definition provided, the group that did not receive the treatment will be called a control group, thus the correct answer.

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A community college has a math placement exam that has a mean of 65 and a standard deviation of 8.2. If a student takes the exam
Marat540 [252]

Answer:

The score that cuts off the bottom 2.5% is 48.93.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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\mu = 65, \sigma = 8.2

What is the score that cuts off the bottom 2.5%

This is X when Z has a pvalue of 0.025, so X when Z = -1.96.

Z = \frac{X - \mu}{\sigma}

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X = 48.93

The score that cuts off the bottom 2.5% is 48.93.

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D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}

Learn more about set-builder notation here: brainly.com/question/17238769

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