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S_A_V [24]
3 years ago
7

Daniel and Audrey are reading the same book. At the beginning of the month, Daniel was on page 49 and Audrey was on page 22. Dan

iel will read 17 pages per day and Audrey will read 20 pages per day. Let
D
D represent the page of the book that Daniel is on at the end of
t
t days into the month, and let
A
A represent the page of the book that Audrey is on at the end of
t
t days into the month. Write an equation for each situation, in terms of
t
,
t, and determine what page Daniel and Audrey will be on on the day they are both on the same page.


Can you plz help me because it says that it’s wrong?

Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

202

Step-by-step explanation:

So it has to end in 2 because 20t+22 will always be a 2.

day1:

17x1+49=66

no 2

day2:

17x2+49=83

odd

day3:

D=100

no 2

day4:

odd

day5:

D=134

no 2

etc

keep adding 17 to D until you get one that ends in 2

D=202

A=202

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Raymond has 120 books on his bookshelf that he has not read. He plans on reading 3 books per week until there are only 24 books
Oksi-84 [34.3K]

Answer:  The correct option is (A) 120-3w=24;~32.

Step-by-step explanation:  Given that Raymond has 120 books on his bookshelf that he has not read. He plans on reading 3 books per week until there are only 24 books that he still needs to read.

We are to find the equation that can be used to determine the number of weeks it will take Raymond to have only 24 books left.

Also, we are to find the number of weeks.

The number of weeks  it will take Raymond to have only 24 books left is represented by 'w'.

We have

number of books read by Raymond is 1 week = 3.

So, number of books read by Raymond is w weeks = 3w.

Since, there are total 120 books on his bookshelf, so the number of books left to read after w weeks will be

120-3w.

According to the given information, we get

120-3w=24\\\\\Rightarrow 3w=120-24\\\\\Rightarrow 3w=96\\\\\Rightarrow w=32.

thus, the required equation is 120-3w=24 and number of weeks is 32.

Option (A) is correct.

8 0
3 years ago
How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?
Makovka662 [10]

Answer:

24,192.

Step-by-step explanation:

The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

The number of permutations of the other 4 numbers is 9P4

= 9! /  (9-4)!

= 3024

Now we multiply by the 8:

3024 * 8

= 24,192.

6 0
3 years ago
Which points on the number line represent the quotients of these expressions? 12 divided by -6 and -15 divided by -3
yaroslaw [1]

Answer:

2,5

Step-by-step explanation:

basta isipin mo BWHAHAHAHAHHA balakadan

4 0
3 years ago
Help me out please I’m stuck
zysi [14]
Your answer is Y=-4 5
———
- -6, 6
4 0
3 years ago
What is the 5th term of an arithmetic sequence if t2 = -5 and t6 = 7
RUDIKE [14]
An=Asub1+d(n-1)
Asub5= -5+½(4)
=-5+7
=2
5 0
3 years ago
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