Answer:
-44
Step-by-step explanation:
9514 1404 393
Answer:
P = 3x +32
Step-by-step explanation:
If we assume the short vertical edge at top center is 10 yards, as it was in two previous problems with this geometry, then we can find the area of the present parking lot as ...
(x-2)(3x) + x(3x -10) +2x(40) = 6x^2 +64x
where the left vertical rectangle is 3x high and x-2 wide; the center area between vertical rectangles is (2x-2)-(x-2) = x wide and (3x-10) high; and the right vertical rectangle is (x-2 +3x)-(2x-2) = 2x wide and 40 high.
As we said, the right vertical rectangle is 2x wide, so the area that has P as one of its dimensions is ...
A = LW = P(2x)
We want this to be the same as the existing area, so ...
2Px = 6x^2 +64x
P = 3x +32 . . . . . divide by 2x
Step-by-step explanation:
X1 = 1
X2 = (X1) 2 - X1
X2 = 2 - 1
X2 = 1. implies that the second term of the sequence is 1.
The maximum units is 200 and , Total revenue is $8,000
<u>Step-by-step explanation:</u>
Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:
We have following function as
. Let's differentiate this and equate it to zero to find value of x for which the function is maximum!
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Now , Value of function at x=200 is :
⇒ 
⇒ 
⇒ 
Therefore , The maximum units is 200 and , Total revenue is $8,000