What is the quotient of k

If n =270 and (p-hat) =0.43, find the margin of error at a 99% confidence level.. give answer to 3 decimals

Troyanec [42]

Answer:

0.078

Step-by-step explanation:

Margin of error = z√(p(1-p)/n)

Given

p-hat = 0.43

n = 270

z at 99% confidence interval = 2.576

Substitute

MOE = 2.576√0.43(1-0.43)/270

MOE = 2.576√0.43*0.57/270

MOE = 2.576√0.2451/270

MOE = 2.576*0.030129

MOE = 0.078

Hence the margin og error is 0.078

7 0

2 years ago

What is (x,y) (x-4, y+2)? A. rotation B. reflection C. Transition D. Dilation

Novosadov [1.4K]

Answer:

im pretty sure it’s a sorry if i’m wrong

Step-by-step explanation:

5 0

3 years ago

A triangle can exist with side lengths 15cm, 22cm, and 35cm.<br> A<br> False<br> B<br> True

Advocard [28]

Answer:

The answer is False maybe

8 0

3 years ago

A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

3 years ago

If you were to be driving in a car at a high amount of speed and shot a gun out the window forward (towards the windshield forwa

marin [14]

Answer:

If you shoot the bullet off the back of the car , the bullet will still be moving away from you and the gun at 1,000 mph, but now the speed of the train will subtract from the speed of the bullet. Relative to the ground, the bullet will not be moving at all, and it will drop straight to the ground.

Step-by-step explanation:

7 0

3 years ago

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