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3 years ago

An astronaut brings a cube from the Earth to the Moon.

Physics

1 answer:

olganol [36]3 years ago

3 0

Answer:

Answer D. Inertial mass constant, weight decreases.

Explanation:

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2. A rod 14.0 cm long is uniformly charged and has a total charge of -22.0 μC. Determine the magnitude and direction of the net

Sloan [31]

Explanation:

It is given that,

Length of rod, l = 14 cm = 0.14 m

Total charge, $Q=-22\ \mu C=-22\times 10^{-6}\ C$

We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m

Electric field at the axis of rod is given by :

$E=\dfrac{\lambda}{2\pi \epsilon_o z}$

Where

$\lambda$ is the linear charge density, $\lambda=\dfrac{Q}{l}$

So, $E=\dfrac{Q}{2\pi \epsilon_o zl}$

$E=\dfrac{-22\times 10^{-6}}{2\pi \times 8.85\times 10^{-12}\times 0.36\times 0.14}$

E = −7849988.22 N/C

$E=-7.84\times 10^6\ N/C$

Negative sign shows the direction of electric field is inward in all direction. Hence, this is the required solution.

7 0

3 years ago

An object having a mass of 11.0 g and a charge of 8.00 ✕ 10-5 C is placed in an electric field E with Ex = 5.70 ✕ 103 N/C, Ey =

dezoksy [38]

Answer : $F_{x} = 45.6\times10^{-2}\ N$ , $F_{y} = 3040\times10^{-5} N$ and $F_{z} = 0\ N$

Explanation :

Given that,

Charge of the object q = $8.00\times 10^{-5}\ C$

Electric field in x-direction $E_{x} = 5.70\times10^{3}\ N/C$

Electric field in y- direction $E_{y} = 380\ N/C$

Electric field in z - direction $E_{z} = 0$

Now, using formula

$F = q E$

Now, the force on the object in x- direction

$F_{x} = 8.00\times10^{-5} C \times5.70\times10^{3} N/C$

$F_{x} = 45.6\times10^{-2}\ N$

The force on the object in y- direction

$F_{y} = 8.00\times10^{-5}\ C\times 380\ N/C$

$F_{y} = 3040\times10^{-5} N$

The force on the object in z- direction

$F_{z} = 8.00\times10^{-5}\ C\times 0$

$F_{z} = 0\ N$

Hence, this is the required solution.

8 0

4 years ago

Object A has a mass of 100 grams. Object B has a mass of 150 grams. They are both traveling at the same velocity. Which can you

Tanzania [10]

Object B has a greater inertia i think, it has a greater momentum anyway

6 0

3 years ago

A wire of cross-sectional area 5.00 106 m2 has a resistance of 1.75 O. What is the resistance of a wire of the same material and

MakcuM [25]

Answer:

the resistance of the second wire is 1 ohm.

Explanation:

Given;

cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²

resistance of the first wire, R₁ = 1.75 ohms

cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²

resistance of the second wire, R₂ = ?

The resistance of a wire is given as;

R ∝ $\frac{L}{A}$

Since the length of the two wires is constant

R₁A₁ = R₂A₂

$R_2 = \frac{R_1A_1}{A_2} \\\\R_2 = \frac{1.75\ \times \ 5.00\times 10^6}{8.75\times 10^6} \\\\R_2 = 1 \ ohm$

Therefore, the resistance of the second wire is 1 ohm.

6 0

3 years ago

Given that the speed of sound in air is 330m/s ,calculate the frequency of a note which setup a wavelength of 5cm in air.Is this

Pie

Explanation:

v = wavelength x frequency

330 = 5 . 10-² m x f

f = 6600 Hz

the frequency that human can hear is about 20 Hz - 20000 Hz

so human can hear the note.

3 0

4 years ago

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