Answer:
The mass of the heaviest box you will be able to move with this applied force = 61.4 kg
Explanation:
From the diagram attached, the forces acting on the box include the weight of the box, applied force on the box, normal reaction of the surface on the box and the Frictional force in the opposite direction to the applied force.
For the box to be able to move, the applied force must have a horizontal component that at least matches the Frictional force between the box and the surface. This is the force balance in the horizontal direction.
Resolving the applied force into horizontal and vertical components,
Fₓ = 750 cos 25° = 679.73 N
Fᵧ = 750 sin 25° = 316.96 N
Doing a force balance in the vertical axis,
N = (mg + 316.96)
Frictional force = μN = μ (mg + 316.96)
μ = 0.74, g = 9.8 m/s²
Frictional force = Fᵧ
μ (mg + 316.96) = 679.73
0.74(9.8m + 316.96) = 679.73
7.252m + 234.5504 = 679.73
7.252m = 679.73 - 234.5504 = 445.1796
m = (445.1796/7.252)
m = 61.4 kg
Hope this Helps!!!
Explanation:
The object's weight on Earth is 5.0 N, so its mass is:
F = ma
5.0 N = m (10 m/s²)
m = 0.50 kg
The acceleration on the moon is g/6 = (10 m/s²) / 6 = 1.67 m/s².
The velocity it reaches after 3.0 seconds is:
v = at + v₀
v = (1.67 m/s²) (3.0 s) + (0 m/s)
v = 5 m/s
So the momentum is:
p = mv
p = (0.50 kg) (5 m/s)
p = 2.50 kg m/s
Answer:a substance with low ability or no ability to conduct energy
Explanation:
Answer:
I = 3.82 x 10^(−7) A
Explanation:
The formula for magnetic field at the centre of a loop is given as;
B = μI/2R
Where μ is a magnetic constant with a value of 12.57 × 10^(−7) H/m.
I = current
R = Radius = 16/2 = 8cm or 0.08m
B = 3.0×10^(−12) T
So making I the subject of the formula, we obtain ;
I = 2RB/μ
Thus, I = [2 x 0.08 x 3.0×10^(−12)]/12.57 × 10^(−7)
I = 3.82 x 10^(−7) A
Answer:
The optimum wavelength = (8.863 × 10⁻⁷) m = 886.3 nm
Explanation:
The light that will generate the photovoltaic energy of 1.4 eV will must have that amount of energy
Energy of light waves is given as
E = hf
h = Planck's constant = (6.626 × 10⁻³⁴) J.s
f = Frequency of the light
The frequency is then further given as
f = (c/λ)
c = speed of light = (3.0 × 10⁸) m/s
λ = wavelength of the light = ?
E = (hc/λ)
λ = (hc/E)
Energy = E = 1.4 eV = 1.4 × 1.602 × 10⁻¹⁹ = (2.2428 × 10⁻¹⁹) J
λ = (6.626 × 10⁻³⁴ × 3.0 × 10⁸)/(2.2428 × 10⁻¹⁹)
λ = (8.863 × 10⁻⁷) m = 886 nm
Hope this Helps!!!