It is probably B x has to be more than 7 but can be equal 7 at the same time.
<span>To solve this equation we
can first assume that both a and b are nonzero real numbers. Hence,
A = 1 b = 1
<span><span>
1.
</span>2 (1) + 1 =
2(1)</span>
<span><span>
2.
</span><span> 2 + 1 = 2: now this a false equation since
there is not equality, the equation cannot retain the equal sign but will
become 2 + 1 > 2. Leaving the relationship unequal.
</span></span>However, the alternative to
this problem is to be b = 0. To oversee the rule in order to solve the equation
retaining it as an “equation”. Further, there is no other solution for this
equation.
A = 1 b = 0
<span>1.
Which
becomes 2(1) + 0 = 2(1)</span>
<span><span>
2.
</span><span> 2 + 0 = 2 :
3. 2 = 2. Here we can observe the
equality. </span></span>
</span>
Answer:
rotated
Step-by-step explanation:
rotated
reflected
translated
dilated
Answer:
The answer is 1.0556. Hope that helps you!
Step-by-step explanation:
